If Statement
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t=input('Enter a positive octal number')
if isnumeric(t)
s=num2str(t)
* if length*
disp([s ' is an invalid positive octal number'])
else
I am creating a octal to decimal calculator for class. We cannot use the one Matlab has installed. I have the rest of my code written but I am having trouble what my code should be at the beginning of my if statement. I know length is prompting for the array. I guess what I am asking is how would I write that part of the code to show if the number isnt a positive valid octal number
1 件のコメント
Image Analyst
2011 年 10 月 28 日
I don't know what you're asking. An valid octal number can be any length from one digit up to dozens or more. Do you really mean how can you scan it to make sure that only characters 0-7 are present in the user's entry?
回答 (1 件)
Fangjun Jiang
2011 年 10 月 28 日
For that, I think taking the input as a string is better.
t=input('Enter a positive octal number: ','s');
check=t>'0' & t<'7';
if ~all(check)
disp([t,' is an invalid positive octal number']);
end
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