Anonymous functions and conditional logic? (one line step function)

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Adam Attarian
Adam Attarian 2011 年 10 月 28 日
コメント済み: Walter Roberson 2022 年 3 月 26 日
Hi Folks,
It looks like you can't use conditional logic in an anonymous function -- which is too bad because I'm trying to do a step function as an anon function. I'd like to do it as a one liner, something like:
step = @(t) if t>t0 return a, elseif t<=t0 return b, end,
but MATLAB doesn't like that of course. In my case, a=10e-4 and b=10e-6, just in case anyone is wondering. Is there something similar that I can do? I've been trying to modify tanh(x) to go from a to b, but I can't quite get the syntax right. I'd like an anon fun because it would be an element in a structure array if I get this coded right.
Thanks for the help! Adam

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Fangjun Jiang
Fangjun Jiang 2011 年 10 月 28 日
It can be done in a twisted way. I am not sure how much value it provides. step is a built-in function so avoid using it.
h=@(t) a*(t>5)+b*(t<=5)
or with the complete parameters
h=@(t,t0,a,b) a*(t>t0)+b*(t<=t0)
  6 件のコメント
Piyush Kant
Piyush Kant 2022 年 3 月 26 日
What if the value to be returned is a string?
Walter Roberson
Walter Roberson 2022 年 3 月 26 日
In the case of string objects I would suggest having a string array being indexed by (2 minus logical value). This would select the first string for true and the second for false

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