フィルターのクリア

How to solve (ax+2by) = -5 & (-3x+2by) = 7, in MAT Lab by symbolic math add ons?

1 回表示 (過去 30 日間)
Jawed
Jawed 2023 年 5 月 23 日
コメント済み: Anish Gupta 2023 年 5 月 23 日
Solve (ax+2by) = -5 & (-3x+2by) = 7, in MATLab by symbolic math add ons?
  2 件のコメント
Dyuman Joshi
Dyuman Joshi 2023 年 5 月 23 日
What are a and b supposed to be?
Also look into syms
Jawed
Jawed 2023 年 5 月 23 日
I want this solution for variable 'x' and 'y', 'a' & 'b' are constant. Thanks.

サインインしてコメントする。

採用された回答

Anish Gupta
Anish Gupta 2023 年 5 月 23 日
Hello,
As per my understanding, you want to symbolically solve two equations. However, it is not clear from your question, for which variable you want to solve the questions. So, I am assuming you want to solve for either 'x' and 'y', or 'a' and 'b'. Here is a code which shows how to do this:
syms x y a b
eqn=[a*x + 2*b*y==(-5),-3*x+2*b*y==7];
solve(eqn,[x,y])
ans = struct with fields:
x: -12/(a + 3) y: (7*a - 15)/(2*(3*b + a*b))
Here is the solution for variables 'a' and 'b'
solve(eqn,[a,b])
ans = struct with fields:
a: -(3*(x + 4))/x b: (3*x + 7)/(2*y)
I hope this resolves your query
  2 件のコメント
Jawed
Jawed 2023 年 5 月 23 日
Thank you very much for providing solution. I want this solution for variable 'x' and 'y'. Thanks again.
Anish Gupta
Anish Gupta 2023 年 5 月 23 日
The solution for 'x' and 'y' are the first three lines of the code
syms x y a b
eqn=[a*x + 2*b*y==(-5),-3*x+2*b*y==7];
solve(eqn,[x,y])
ans = struct with fields:
x: -12/(a + 3) y: (7*a - 15)/(2*(3*b + a*b))

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCalculus についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by