Error using title of plot

Hi,

I want to use plot with title command. But when I try title of :

title(['Plots of ... with beta1=',num2str(beta1)','alphabar=',num2str(alphabar)]);

it gives me error saying :

Error using horzcat
Dimensions of matrices being concatenated are not consistent.

But without

beta1=',num2str(beta1)','alphabar=',num2str(alphabar)])

it is working. So beta1 and alphabar should be indicated somewhere in figure but how?

Answer 1

[Mahdiyar]

Hi Meva

Can you send the values of "beta1" and "alphabar"?

The problem is about the dimention of "beta1" or "alphabar". One of them is a column vector.

Please check the value of these two variables.

Regards,

[Meva]

Hi Mahdiyar,

Thanks, these are just numbers.

alpha = 0.1;
beta1 = radtodeg(pi)*alpha;
alphabar = 1;

[Meva]

and If I try without beta1 in title

(let us say the trouble comes from radtodeg) it is still giving the same error.

Actually I have been facing to this problem

when I include the num2str in the title line for a while.

[Mahdiyar]

Hi

you just did one little mistake. follow the code below. I tried and it works

alpha = 0.1;
beta1 = radtodeg(pi)*alpha;
alphabar = 1;

plot(1:10,1:10)

title(['Plots of ... with beta1=',num2str(beta1),'alphabar=',num2str(alphabar)]);

The problem is that the size of num2str(beta1) is 1*1 and it is counted as row vector but num2str(beta1)' is also 1*1 but it is counted as column vector.

Regards

[Meva]

I cannot understand the following:

----The problem is that the size of num2str(beta1) is 1*1 and it is counted as row vector but num2str(beta1)' is also 1*1 but it is counted as column vector.

Best

[Meva]

My actual plot command

plot(xx, u13,xx,u23,xx,p12,xx,p22)

If I use yours, how the program undrestand the data to be plotted?

[Mahdiyar]

the point is that you put one " ' " extera. that is all.

[Meva]

thank you that solved the problem.

Answer 2

[Image Analyst]

That's why I prefer to use sprintf() instead of [ ].

caption = sprintf('Plots of ... with beta1=%f, alphabar=%f', beta1, alphabar);
title(caption, 'FontSize', 25);

[Meva]

But it says

   Undefined function or variable 'caption'.

when I try it.

[Image Analyst]

What happens if you take off the semicolon? It should definitely define it:

caption = sprintf('Plots of ... with beta1=%f, alphabar=%f', beta1, alphabar)

The only way for caption to not be defined is if it completely skipped the line. But if it skipped that line, it wouldn't have executed the title() line either. Makes no sense.

[Meva]

I took off the semicolon but it says the same thing. Thanks.