tf and damp, all need the numerical coefficients of the transfer function
2 ビュー (過去 30 日間)
古いコメントを表示
But I want the symbolic operation, how can I do ?
8 件のコメント
Walter Roberson
2023 年 5 月 15 日
poles = solve(D, 'maxdegree', 4);
Typically this will create a quite long output. The exact symbolic solutions for the roots of degree 4 are complicated. When any of the coefficients are symbolic variables then there is little hope that you will get nice outputs. If all of the coefficients are numbers then from time to time you will get nice numeric solutions... but pretty much only for the case that someone deliberately created an easy form
回答 (1 件)
Sam Chak
2023 年 5 月 21 日
Hi @li hu
Finding the poles (roots of the denominator) is like solving polynomial equations.
However, if it is 5th-degree and higher polynomial, then it cannot be solved algebraically in terms of a finite number of additions, subtractions, multiplications, divisions, and root extractions.
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Calculus についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!