フィルターのクリア

Transfer function RC - circuit

12 ビュー (過去 30 日間)
Alexandru Miculescu
Alexandru Miculescu 2015 年 4 月 4 日
回答済み: Alexandru Miculescu 2015 年 4 月 4 日
Hi!
Suppose R = C = 1 then the transfer function from the input voltage to the voltage across the capacitor is 1/ (s+1). So Vc(S) / V(S) = 1/(s+1). Getting back to time-domain: Vc(t) = V(t) * e^-t. What's wrong here? It should have been V(t) ( 1 - e^-t ).
The rising function is step( transfer_function ) and the decaying one is ezplot ( ilaplace ( transfer_function )). Why are these two not the same?
Thank you!
  1 件のコメント
Star Strider
Star Strider 2015 年 4 月 4 日
What does the circuit look like?
Where are you measuring the output voltage?

サインインしてコメントする。

回答 (1 件)

Alexandru Miculescu
Alexandru Miculescu 2015 年 4 月 4 日
Problem solved! It had to been multiplied with 1/s (step response) then converted to time domain. Thank you anyway!!!

カテゴリ

Help Center および File ExchangeSpectral Measurements についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by