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how to improve a model predictive control in order to get a lower cost function for the system?

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Hello everyone,
I have implemented a model predictive control using a plant model (which has some disturbance in it), then I run the model and I got the cost function(figure2) equal to 8, and the inputs and ouptuts as shown in figure 3, and figure 4 shows the performance of the test which looks good, and the last figure include the parameters of the model, and my first question is how can I improve the model (by lowering the cost function)? could it be by changing the state estimation? or something.
and for the parameters of the simulink, they are as follow: constraints for the input and output, Nc, Np and sampling time.

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Emmanouil Tzorakoleftherakis
Emmanouil Tzorakoleftherakis 2023 年 4 月 27 日
You basically want to get a more aggressive response if I understand correctly, meaning that your outputs will converge faster to the desired values. First thing to try is increase the cost weights on these particular states.
  5 件のコメント
jana nassereddine
jana nassereddine 2023 年 5 月 4 日
but the question is how? I just looked through the MPC and The plant model, and there is nothing that indicate that I can change the initial values of the states or other, and thank you a lot for your help
jana nassereddine
jana nassereddine 2023 年 5 月 5 日
Hey again,
I just tried to apply different scale factors, and I got differents results for the cost function,but why does a scaler factor affect a cost function?
so first the cost function was 8,5*10^(24), then it was 4.5*10^5,
and I tried to change the optimal value for the input and the ouput, but I got higher cost function, except when the optimal value are 0 or 1, the cost was 4.5*10^5, as before, so why was the cost function better when the optimal value were 0 or 1?
and my last question is about the cost function: I have an article where they got the results about the cost function and they put it in a table indicating the cost function as 8,... and the cost function that I got was 8,5*10^25, so is it the same? I will upload a figure explaining, but the figue is 4.5 10^5, instead of 8.5*10^25, so what do you think?

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