Multistart apparently does not respect the supplied initial points
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Mohammad Shojaei Arani
2023 年 4 月 13 日
コメント済み: Mohammad Shojaei Arani
2023 年 4 月 15 日
Hello,
I have a simple, but annoying, problem about multistart in MATLAB. Consider the following example from MATLAB description of multistart:
fun = @(x) x.^2 + 4*sin(5*x);
opts = optimoptions(@fmincon,'Algorithm','sqp');
problem = createOptimProblem('fmincon','objective',...
fun,'x0',2.5,'lb',-5,'ub',5,'options',opts);
ms = MultiStart;
[x,f] = run(ms,problem,1)
This gives me the following answer
The local solver ran once and converged with a positive local solver exit flag.
x =
-2.7713
f =
3.8366
But, I expected to roughly get x=2.159 based on the initial point x0=2.5 I supplied. I attach a figure which shows my initial point (open circle) and my expection of local minimum (red star).
Any idea?
Thanks in advance!
Babak
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Alan Weiss
2023 年 4 月 14 日
The only error here is your expectation that fmincon always converges to the closest local minimum. It does not.
fun = @(x) x.^2 + 4*sin(5*x);
opts = optimoptions(@fmincon,'Algorithm','sqp');
problem = createOptimProblem('fmincon','objective',...
fun,'x0',2.5,'lb',-5,'ub',5,'options',opts);
ms = MultiStart;
[x,f] = run(ms,problem,1)
% Now let's see where fmincon goes
[x2,f2] = fmincon(problem)
Understand? MultiStart works as documented. When you call it with 1 run, it takes the supplied start point and proceeds to call fmincon. The error was expecting fmincon to converge to the closest local minimum.
Alan Weiss
MATLAB mathematical toolbox documentation
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