bypass an "if" within another using a flag
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Hi everyone,
I have the code below:
a=5; b=4; c=3; d=2;
if a>b
if b>c % ====> this
if c>d
disp('i''m in!')
end
end % ======> this
end
Is it possible I bypass the " if b>c" using a flag?
e.g. FLAG=1, include this if, and FLAG=0, bypass this if.
Thanks!
0 件のコメント
採用された回答
Walter Roberson
2023 年 4 月 8 日
You might mean either of two different things:
First possibility:
a=5; b=4; c=3; d=2;
if a>b
if FLAG == 1 && b>c
if c>d
disp('i''m in!')
end
end % ======> this
end
In the above case, if b>c is only tested if FLAG is 1 -- but c>d is not tested if FLAG is not 1.
Second possibility:
a=5; b=4; c=3; d=2;
if a>b
if FLAG ~= 1 || b>c
if c>d
disp('i''m in!')
end
end % ======> this
end
In this case, the b>c test is only done if FLAG == 1, and if FLAG is not 1, then you go on to c>d anyhow.
2 件のコメント
Image Analyst
2023 年 4 月 8 日
編集済み: Image Analyst
2023 年 4 月 8 日
Unless you've left out a lot of code (especially after the b>c block, there is no reason to even enter the a>b block. You could simply do
if a>b && FLAG
if b>c
if c>d
disp('i''m in!')
end
end % ======> No more code after this block
end
Of course the b>c and c>d could even be combined into a single test sine the c>d is the only thing in the block (again, assuming you have not left out additional code):
if a>b && FLAG
if b>c && c>d
disp('i''m in!')
end % ======> No more code after this block
end
その他の回答 (1 件)
Image Analyst
2023 年 4 月 8 日
Since the b>c test occurs only inside the a>b block, and it's the only thing in the a>b block, you could simply do
if a>b && b>c
if c>d
disp('i''m in!')
end
end
1 件のコメント
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