How to make a phase diagram plot?

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Wing Nam
Wing Nam 2023 年 4 月 1 日
回答済み: Sam Chak 2023 年 12 月 16 日
Hi all. I have an ODE and I have already found the general solution of.
How can I plot a phase diagram with some initial value like y(1)=1?
  1 件のコメント
Sai
Sai 2023 年 4 月 4 日
I am not sure if the solution is correct because when x is equal to 1, y is not equal 1.

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回答 (2 件)

Sai
Sai 2023 年 4 月 4 日
Hi Wing,
I understand that you want to make a phase diagram plot for the above differential equation.
Please refer to the below code snippet.
function dydx = diff_eq(x,y)
dydx = [y(2); (exp(-x)-2*(x-1)*y(2)-(x-2)*y(1))/x];
end
Place two code snippets in different .m files. But the above code snippet in diff_eq.m file
[x,y] = ode45(@diff_eq,[1 5],[1; 1]);
plot(y(:,1),y(:,2));
xlabel('y(1)');
ylabel('y(2)');
please refer to the below documentation ink for more information on using ‘ode45’
I hope this helps you to resolve the query

Sam Chak
Sam Chak 2023 年 12 月 16 日
If the analytical solution exists, then you can solve the ODE symbolically using the dsolve() command. From the results, you can plot out the phase portrait diagram using the fplot() command.
%% Setup the ODE in symbolic form
syms y(x) z(x)
Dy = diff(y,x); % dy/dx
ODEqn = diff(y,x,2) == (exp(-x) - 2*(x - 1)*Dy - (x - 2)*y)/x
ODEqn(x) = 
%% General solution
yGenSol(x) = dsolve(ODEqn)
yGenSol(x) = 
%% Particular solution
init = [y(1)==1, Dy(1)==0]; % initial values
yParSol(x) = dsolve(ODEqn, init)
yParSol(x) = 
DyParSol = simplify(diff(yParSol), 'steps', 100)
DyParSol(x) = 
%% Plot time responses of states
figure(1)
T1 = tiledlayout(2, 1);
nexttile(T1)
fplot( yParSol, [1 20]), grid on, ylabel('y(x)')
nexttile(T1)
fplot(DyParSol, [1 20]), grid on, ylabel('dy/dx')
title( T1, '2nd-order System')
xlabel(T1, 'Time')
ylabel(T1, 'Staes')
%% Plot phase portrait diagram
figure(2)
fplot(yParSol, DyParSol, [1 20]), grid on
title('Phase Portrait')
xlabel('y(x)'), ylabel('dy/dx')

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