Plot length of time between two events

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Maria
Maria 2023 年 3 月 30 日
コメント済み: Chris 2023 年 4 月 6 日
I have a table with 3 columns: Sensor ID, Start Time, Stop Time, like this:
2 '20 Mar 2023 18:01:24.318' '20 Mar 2023 18:14:29.431'
2 '20 Mar 2023 20:01:17.651' '20 Mar 2023 20:13:36.931'
2 '21 Mar 2023 06:23:12.515' '21 Mar 2023 06:37:34.666'
2 '21 Mar 2023 08:25:49.680' '21 Mar 2023 08:34:08.341'
3 '20 Mar 2023 23:09:56.209' '20 Mar 2023 23:23:32.154'
3 '21 Mar 2023 01:17:08.676' '21 Mar 2023 01:31:28.003'
3 '21 Mar 2023 10:20:17.002' '21 Mar 2023 10:22:52.180'
3 '21 Mar 2023 12:21:13.756' '21 Mar 2023 12:37:30.450'
4 '20 Mar 2023 16:50:51.910' '20 Mar 2023 16:53:08.560'
4 '21 Mar 2023 01:11:16.404' '21 Mar 2023 01:19:06.159'
4 '21 Mar 2023 03:07:32.598' '21 Mar 2023 03:22:05.176'
4 '21 Mar 2023 13:31:47.726' '21 Mar 2023 13:43:56.867'
4 '21 Mar 2023 15:30:50.827' '21 Mar 2023 15:43:57.428'
And I want to plot, the sensor number on the y axis, and in the x axis the length or time between start time and stop time. Basically, I need like a horizontal error bar, where the "error" is the time between start and stop time.
I can create this "error" and plot, but I was wondering if there was an easier/mote straight forward way of doing.
Here is an example of the plot I want:

採用された回答

Chris
Chris 2023 年 3 月 30 日
編集済み: Chris 2023 年 3 月 30 日
Without your code, it's difficult to say what is "easier." Errorbar plots are pretty simple.
You could use patch...
% My table is "t" with variables "sid (double)","starttime (datetime)", and "stoptime (datetime)"
nsens = 32; % Or however many sensors you have
clrs = lines(nsens);
barhalfheight = 0.1;
x = [t.starttime, t.stoptime, t.stoptime, t.starttime];
y = t.sid + barhalfheight.*[-1, -1, 1, 1];
c = clrs(t.sid,:)
figure
for idx = 1:size(x,1)
patch(x(idx,:),y(idx,:),c(idx,:))
end
set(gca,'YTick', 1:nsens)
set(gca,'YTickLabel', "Sensor " + (1:nsens))
  9 件のコメント
Maria
Maria 2023 年 4 月 5 日
using Matlab Online, worked for both ways, as expected.
converting datetime to posixtime worked too.
Thank you again @Chris!
Chris
Chris 2023 年 4 月 6 日
No problem. :)

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