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Conversion of float to int16

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Geerthy Thambiraj
Geerthy Thambiraj 2023 年 3 月 12 日
コメント済み: Geerthy Thambiraj 2023 年 3 月 12 日
Hi everyone
I have ECG data in float, and I would like to convert it into int16 to be used by the manually created toolbox. To convert float into int16, I multiplied data with 2^15 and cast it. However, the output of the toolbox is not the desired output. So I tried to analyze the previous ECG data and how it was converted to int16 format(2 bytes), yet I did not understand how data_float is converted into data_int16(both mat files are attached). Any suggestions would be highly appreciated.
Thank you.
  2 件のコメント
Jan
Jan 2023 年 3 月 12 日
What is the corresponding code in "the manually created toolbox"? Profer to post the code instead of paraphrasing its intention.
Geerthy Thambiraj
Geerthy Thambiraj 2023 年 3 月 12 日
Thank you. I apologize.
Input to the code is in .bin format and this is how the .bin file is created once its been converted to the int16 format.
Once the rawdata.bin file is created, it is read by the part of the toolbox (the second part of the code).
% Data_float into int16 and .bin file created
ecg_int=data_float*32767; % multiplying by 2^16-1 but i didnt get the desire output
val=cast(ecg_int,'int16');
fid_write = fopen('rawdata.bin','w');
fwrite(fid_write,val','int16');
fclose(fid_write);
% Read by the part of the code in the toolbox
samplestepsize = 600000;
overlapstepsize = 2500;
numfullreads = 0;
fid = fopen(rawdata.bin,'r');
fileoffset = 0;
fseek(fid,fileoffset,'bof');
if readnum == 0
data = fread(fid, [1,samplestepsize], 'int16'); % Read data
else
data = fread(fid, [1,samplestepsize+overlapstepsize], 'int16');
end;

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回答 (2 件)

Walter Roberson
Walter Roberson 2023 年 3 月 12 日
s1 = load('data_float.mat');
data_float = s1.data_float;
s2 = load('data_int16.mat');
data_int16 = s2.data_int16;
A = [data_float(:), ones(numel(data_float),1)];
b = double(data_int16(:));
coeffs = A\b
coeffs = 2×1
896.9373 645.8154
projected = coeffs(1) .* data_float(:) + coeffs(2);
difference = projected - b;
subplot(4,1,1); plot(data_float); title('data\_float');
subplot(4,1,2); plot(data_int16); title('data\_int16');
subplot(4,1,3); plot(data_int16); hold on; plot(projected); hold off; legend({'int16', 'projected'});
subplot(4,1,4); plot(difference); title('difference projected minus actual')
If there were a linear relationship between the float and int16 then it would be captured perfectly (to within round-off) by the projected data. But you can see that the difference between projected and actual starts low and ends high. This tells us that some kind of trend was removed.
  1 件のコメント
Geerthy Thambiraj
Geerthy Thambiraj 2023 年 3 月 12 日
Thank you very much for the detailed analysis. This confirms the direct casting to int16 from float will not yield the desired results. Let me recheck the process. Thank you.

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Jan
Jan 2023 年 3 月 12 日
The signals are not related by a linear transformation:
The signals look similar, but the int16 version has a downwards trend at the end and the peak heights are not equivalent. Maybe a filter was applies also?
Instead of guessing the applied transformation, it would be reliable to look in the original code or to ask the author.
  1 件のコメント
Geerthy Thambiraj
Geerthy Thambiraj 2023 年 3 月 12 日
Thank you for your valuable suggestions. The filter is applied once the data is read by the toolbox for further processing.

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