3d plot from knows XYZ
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Hello, i have known list of numbers:
x = [0 10 20 30 0 10 20 0 10 20 30];
y = [0 0 0 0 15 15 15 15 30 30 30 30];
t = [20 22 25 23 22 27 30 25 19 20 18 22];
I used: [X,Y] = meshgrid(x,y), but i'm struggeling with understanding what to do with those t values.
thank you
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回答 (2 件)
Star Strider
2023 年 2 月 26 日
編集済み: Star Strider
2023 年 2 月 26 日
It will be necessary to interpolate them to create a surface.
Try something like this —
x = [0 10 20 30 0 10 20 0 10 20 30];
y = [0 0 0 0 15 15 15 15 30 30 30 30];
t = [20 22 25 23 22 27 30 25 19 20 18 22];
Q = [size(x); size(y); size(t)]
y = y(1:numel(x));
t = t(1:numel(x));
xv = linspace(min(x), max(x), numel(x));
yv = linspace(min(y), max(y), numel(y));
[X,Y] = meshgrid(xv,yv);
F = scatteredInterpolant(x(:),y(:),t(:));
T = F(X,Y);
figure
surfc(X, Y, T)
colormap(turbo)
colorbar
xlabel('X')
ylabel('Y')
zlabel('T')
EDIT — Added axis labels.
.
2 件のコメント
Walter Roberson
2023 年 2 月 26 日
Note: the duplicate point is because the middle "30" is missing in x, so the 0 of the next x cycle lines up with the 15 of the end of the existing y cycle
0 10 20 0
15 15 15 15
whereas if the 30 had not been missed then it would have been (30,15) for that point instead of a second (0,15)
Star Strider
2023 年 2 月 26 日
@Walter Roberson — That is also likely the origin of the vectors not having equal lengths. I just went with the available data.
I’m also assuming that May wants a surf plot because of the meshgrid call.
Devargya chakraborty
2023 年 2 月 26 日
first of all, your vectors should be of the same length.
after that you can use the plot3 command to plot the graph or meshgrid also.
plot3(x,y,t);
meshgrid(x,y,t);
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