I can't running curve in matlab

I have coding for curve in matlab but when I running that coding doesn't display anything. The command window also blank and doesn't display anything. I want this curve like that

[Nur Wahidiyatil]

I have thi coding

t= [0:0.01:0.002];
x = m^2/0.02;
y = (m*(m+0.43))/0.08;
z = (m*(m+0.47))/0.07;
plot(t,x,'b--')
hold on
plot(t,y,'r--')
hold on
plot(t,z,'g--')
hold on
xlabel('Miu')
ylabel('Rekrutmen')
grid
title('Grafik Bifurkasi')

Answer 1

[Walter Roberson]

x = t.^2/0.02;
y = (t.*(t+0.43))/0.08;
z = (t.*(t+0.47))/0.07;

[Nur Wahidiyatil]

This is the output, nothing curve after running

[Askic V]

@Nur Wahidiyatil

This line doesn't make sense:

t= [0:0.01:0.002];

this will not produce an array but only one point.

The following code does make more sense:

t = 0:0.01:1;
x = t.^2/0.02;
y = (t.*(t+0.43))/0.08;
z = (t.*(t+0.47))/0.07;
plot(t,x,'b--')
hold on
plot(t,y,'r--')
hold on
plot(t,z,'g--')
hold on
xlabel('Miu')
ylabel('Rekrutmen')
grid
title('Grafik Bifurkasi')

[Nur Wahidiyatil]

How if I want value of t between 0.00083 until 0.002?

[Walter Roberson]

I suggest you use linspace()

[Nur Wahidiyatil]

I want vallue of t between 0.00083 until 0.002, then I try value of t like that but an output is error

[Walter Roberson]

The default increment of the : operator is 1 . Your second value is less than the first value plus the increment of 1 so the first value is the only one in range.

The : operator does not mean "the entire range of values between the start point and the end point". The : operator is specifically starting at a value, adding an increment to it, adding an increment to that, adding an increment to the previous, and so on until you would exceed the endpoint.

[Nur Wahidiyatil]

Thank you so much