How to find Intersection point of plane and vector/line in 3d
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Hello! Could you please help me why my fucntion does not calculate intersection point I. It gaves me my initial X0, Y0, Z0 coordinate
I used this example
[I ] = planeLocation6(1.5, 3.3371, 0.1820)
function [ I ] = planeLocation6(XBar, YBar, ZBar)
X0 = 1.5;
Y0 = 1.5;
Z0 = 3.0;
Theta0 = 30;
planes(:,:,1) = [0 3 3; 0 0 3; 0 3 0; 0 0 0; 0 0 0];
planes(:,:,2) = [0 0 3; 3 0 3; 0 0 0; 3 0 0; 0 0 0];
planes(:,:,3) = [3 0 3; 3 3 3; 3 0 0; 3 3 0; 3 0 0];
planes(:,:,4) = [3 3 3; 0 3 3; 3 3 0; 0 3 0; 0 3 3];
planes(:,:,5) = [0 3 0; 3 3 0; 0 0 0; 3 0 0; 0 0 0];
planes(:,:,6) = [0 3 3; 3 3 3; 0 0 3; 3 0 3; 0 0 3];
location_plane = 6;
for j=1:6
j==location_plane
plane = planes(:,:,j);
p0 = plane(1,:);
p1 = plane(2,:);
p2 = plane(3,:);
p3 = plane(4,:);
V0 = plane(5,:);
Ri = [X0 Y0 Z0];
Rr = [XBar YBar ZBar];
u = Rr-Ri;
w=Ri-V0;
A = p0-p2;
B = p0-p3;
n=cross(A,B); % normal vector of the Plane
u = Rr-Ri;
w=Ri-V0;
D=dot(n,u);
N=-dot(n,w);
sI = N / D;
I = Ri+ sI.*u;
disp(I);
end
Thank you in advance, BR Aknur
3 件のコメント
Rik
2023 年 2 月 28 日
I recovered the removed content from the Google cache (something which anyone can do). Editing away your question is very rude. Someone spent time reading your question, understanding your issue, figuring out the solution, and writing an answer. Now you repay that kindness by ensuring that the next person with a similar question can't benefit from this answer.
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Bhavana Ravirala
2023 年 2 月 23 日
Hi Ankur,
I understand that you are unable to calculate the intersection point ‘I’.
When I try to run the code at my end, I am getting a value of ‘I’ as Infinity and not the initial values.
You are not getting the intersection point because the dot product of ‘n’ and ‘u’ is zero with the inputs which you have provided to the function. Try giving different inputs to the function such that ‘D’ does not become zero and ‘I’ does not be Infinity.
Hope this helps!!
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