how to extract double value from a string?
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I been trying to figure our how to extract certain numbers from a string with this layout:
D:\MATLAB\noise_check\bilder\Image_230217_1227_Temp_ 42,75.png"
I want to extract the value 42.75 from it. Any ideas how I can do this?
I tried this but it gives me NaN as result:
V = str2double(regexp(fullFileNames,'\d+','match'))
This gives error "Error using sscanf, first argument mustnbe a text scalar".
d = sscanf(fullFileNames, '%d %d %d')
Thanks
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採用された回答
Dyuman Joshi
2023 年 2 月 17 日
移動済み: Star Strider
2023 年 2 月 17 日
"I tried this but it gives me NaN as result: "
Does it? Let's check -
str = "D:\MATLAB\noise_check\bilder\Image_230217_1227_Temp_ 42,75.png";
V = str2double(regexp(str,'\d+','match'))
out = str2double(replace(regexp(str, '\d+,\d+', 'match'),',','.'))
その他の回答 (1 件)
Luca Ferro
2023 年 2 月 17 日
編集済み: Luca Ferro
2023 年 2 月 17 日
assuming the string is always formatted as such you could just:
s='D:\MATLAB\noise_check\bilder\Image_230217_1227_Temp_ 42,75.png'
numS=s(end-8:end-4);
numS2D=replace(numS(',','.'); %necessary since the conversion to double needs . and not ,
numD=str2double(numS2D)
2 件のコメント
VBBV
2023 年 2 月 17 日
s='D:\MATLAB\noise_check\bilder\Image_230217_1227_Temp_ 42,75.png'
numS=s(end-8:end-4)
numS2D=replace(numS,',','.'); % may be you mean this
numD=str2double(numS2D)
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