Multiplication of vectors in for loops

Hi all,

I am wondering how to make this for loop work. Each radius value results in a vector product containing 3 numbers. I wanted those three numbers to occupy each row ( so that each row is a new vector from each radius multiplication ).

radius = [3,3] % contains 9 different values
Tdims= zeros(9,3)
for i = 1: length(radius)
    for j= radius
        Tdims(j,i)= sin (anglesRad) .* radius (j) + ycenter - 100 % each vector product is its own row
    end
end

Answer 1

[Voss]

Possibly this:

radius = rand(3,3); % contains 9 different values
ycenter = 0;
anglesRad = [0 1 2]; % I guess this is a 1-by-3 vector based on your description

nr = numel(radius);
na = numel(anglesRad);
Tdims = zeros(nr,na);
for i = 1:nr
    Tdims(i,:) = sin(anglesRad) .* radius(i) + ycenter - 100; % each vector product is its own row
end

disp(Tdims);

 -100.0000  -99.3458  -99.2931
 -100.0000  -99.8789  -99.8691
 -100.0000  -99.8605  -99.8493
 -100.0000  -99.3679  -99.3170
 -100.0000  -99.9411  -99.9364
 -100.0000  -99.2905  -99.2334
 -100.0000  -99.9297  -99.9240
 -100.0000  -99.3072  -99.2513
 -100.0000  -99.3274  -99.2732

[Jade T]

Excellent, I actually can understand what you did here, and you caught that the center needed to be specified outside the loop. Much appreciated

[Voss]

You're welcome!

Answer 2

[Sulaymon Eshkabilov]

If understood your question correctly, this is how you can get it done:

radius = randi(10, 3, 3); % contains 9 different values
ycenter = 1;
anglesRad = deg2rad([30, 60 90]);
Tdims= zeros(size(radius));
for ii = 1:size(radius,1)
    for jj= 1:size(radius,2)
        Tdims(ii,jj)= sin(anglesRad(ii))* radius (ii,jj) + ycenter - 100; % each vector product is its own row
    end
end
Tdims

Tdims = 3×3

-97.5000 -96.0000 -97.5000 -90.3397 -98.1340 -96.4019 -90.0000 -90.0000 -91.0000