Not enough input arguments for an anonymous function.

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Connor
Connor 2023 年 2 月 12 日
編集済み: the cyclist 2023 年 2 月 12 日
I have this anonymous function:
g = @(x,k) exp(cos(x))^k
I am getting this error:
Not enough input arguments.
Error in solution>@(x,k)exp(cos(x))^k (line 5)
g = @(x,k) exp(cos(x))^k
Im not sure the fix for this because x and k are both represented in the function.
  2 件のコメント
Torsten
Torsten 2023 年 2 月 12 日
g = @(x,k) exp(cos(x)).^k;
g(2,4)
ans = 0.1893
Voss
Voss 2023 年 2 月 12 日
x and k are both represented in the function, yes, but how are you calling the function? If you call it with fewer than two arguments you'll get that error.
% defining g:
g = @(x,k) exp(cos(x))^k
g = function_handle with value:
@(x,k)exp(cos(x))^k
% calling g with 2 arguments:
g(pi,2) % ok
ans = 0.1353
% calling g with 1 argument:
g(pi) % error
Not enough input arguments.

Error in solution (line 1)
g = @(x,k) exp(cos(x))^k
You haven't shown how you are calling the function g, so check on that.

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回答 (1 件)

the cyclist
the cyclist 2023 年 2 月 12 日
編集済み: the cyclist 2023 年 2 月 12 日
I think you probably wanted to raise to the power element-wise, so I changed your function to
g = @(x,k) exp(cos(x)).^k;
But that won't cause the error you got.
How are you calling it? This works:
g = @(x,k) exp(cos(x)).^k;
g(1:5,3)
ans = 1×5
5.0577 0.2870 0.0513 0.1407 2.3420

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