Filter value from multiple columns
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Augusto Gabriel da Costa Pereira
2023 年 2 月 9 日
コメント済み: Mathieu NOE
2023 年 2 月 9 日
I have the following array named "tNino1_2"
I want to filter the value equal to 1 from columns 20, 21, 22, 23 and 24
The script I'm using is below:
xcol=20:1:24
idx=tNino1_2(tNino1_2(:,xcol)==1,:)
The logical indices in position 1 contain a true value outside of the array bounds.
4 件のコメント
Dyuman Joshi
2023 年 2 月 9 日
Do you want to find the position (both row and column values) of elements equal to one between columns 20 to 24?
採用された回答
Mathieu NOE
2023 年 2 月 9 日
hello
I assumed you want all the rows where there is at least one 1 in the columns 20 to 24
xcol=20:1:24;
[r,c] = find(tNino1_2(:,xcol)==1);
[ru,ia,ic] = unique(r);
out = tNino1_2(ru,:);
2 件のコメント
その他の回答 (1 件)
Voss
2023 年 2 月 9 日
編集済み: Voss
2023 年 2 月 9 日
load tNino1_2
"find the values equal to 1 in columns 20 to 24"
[r,c] = find(tNino1_2(:,20:24) == 1)
r is rows and c is columns. Of course, c is relative to columns 20-24 only, so c = 1 means column 20 of the original matrix, c = 2 means column 21, etc.
You can add 19 to c to get the locations of the 1s in the original matrix
c = c+19
Confirm that the elements at those locations are all 1s:
temp = tNino1_2(sub2ind(size(tNino1_2),r,c))
all(temp == 1)
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