How ro fix the "Error using alpha Too many output arguments"?
2 ビュー (過去 30 日間)
古いコメントを表示
Hi Everyone,
I am new to Matlab, but testing a Sift Flow Algorithm, and I am getting this error:
"Error using alpha
Too many output arguments".
Any suggestions will be more than welcome. Many thanks
Here is the code:
im1=imread('a.jpg');
im2=imread('b.jpg');
im1=imresize(imfilter(im1,fspecial('gaussian',7,1.),'same','replicate'),1,'bicubic');
im2=imresize(imfilter(im2,fspecial('gaussian',7,1.),'same','replicate'),1,'bicubic');
im1=im2double(im1);
im2=im2double(im2);
%figure;imshow(im1);figure;imshow(im2);
cellsize=3;
gridspacing=1;
addpath(fullfile(pwd,'mexDenseSIFT'));
addpath(fullfile(pwd,'mexDiscreteFlow'));
sift1=mexDenseSIFT(im1,cellsize,gridspacing);
sift2=mexDenseSIFT(im2,cellsize,gridspacing);
SIFTflowpara.alpha=2*255;
SIFTflowpara.d=40*255;
SIFTflowpara.gamma=0.005*255;
SIFTflowpara.nlevels=4;
SIFTflowpara.wsize=2;
SIFTflowpara.topwsize=10;
SIFTflowpara.nTopIterations = 60;
SIFTflowpara.nIterations= 30;
tic;[vx,vy,energylist]=SIFTflowc2f(sift1,sift2,SIFTflowpara);toc
warpI2=warpImage(im2,vx,vy);
figure;imshow(im1);figure;imshow(warpI2);
% display flow
clear flow;
flow(:,:,1)=vx;
flow(:,:,2)=vy;
figure;imshow(flowToColor(flow));
% this is the code doing the brute force matching
tic;[flow2,energylist2]=mexDiscreteFlow(sift1,sift2,[alpha,alpha*20,60,30]);toc
figure;imshow(flowToColor(flow2));
return;
0 件のコメント
採用された回答
Les Beckham
2023 年 2 月 8 日
Did you mean this line
tic;[flow2,energylist2]=mexDiscreteFlow(sift1,sift2,[alpha,alpha*20,60,30]);toc
to actually be this instead?
tic;[flow2,energylist2]=mexDiscreteFlow(sift1,sift2,[SIFTflowpara.alpha,SIFTflowpara.alpha*20,60,30]);toc
% ^^ this exists ^^
2 件のコメント
Les Beckham
2023 年 2 月 9 日
You are quite welcome. If this answer solved your problem, would you please Accept it? Thanks.
その他の回答 (0 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!