I keep getting "Error using / Arguments must be numeric, char, or logical. " in bayesopt.
2 ビュー (過去 30 日間)
古いコメントを表示
Hi, I'm trying to use "bayesopt", but I keep getting this error.
What did I do wrong?
%% BayesOpt
fxc = @(x) cos(2*pi*(x/4))+exp(x/5);
xvar = optimizableVariable('x',[0,10],'Type','real');
res = bayesopt(fxc,xvar,'MaxObjectiveEvaluations',10,'PlotFcn',[],'AcquisitionFunctionName','lower-confidence-bound','ExplorationRatio',.1);
figure;
plot(res, @plotAcquisitionFunction);
figure;
plot(res,@plotObjectiveModel);
res=resume(res,'MaxObjectiveEvaluation',1);
0 件のコメント
回答 (2 件)
Walter Roberson
2023 年 2 月 7 日
doc bayesopt
fun accepts x, a 1-by-D table of variable values, and returns objective, a real scalar representing the objective function value fun(x).
0 件のコメント
Jan
2023 年 2 月 7 日
Anonymous functions are compact, but less useful for debugging. Use a normal function instead:
fxc = @yourFcn;
xvar = optimizableVariable('x',[0,10],'Type','real');
res = bayesopt(fxc, xvar, 'MaxObjectiveEvaluations', 10, ...
'PlotFcn', [], 'AcquisitionFunctionName', 'lower-confidence-bound', ...
'ExplorationRatio', 0.1);
...
function y = yourFcn(x)
y = cos(2 * pi * x / 4) + exp(x / 5);
end
Run the code again. Now I'd expect it to fail inside yourFcn. Use the debugger to check the details:
dbstop if error
This let Matlab stop, when an error occurs. Run the code again, and when it stops, examine the class of x in the command window:
class(x)
What do you see?
2 件のコメント
Jan
2023 年 2 月 8 日
@DODO, @Walter Roberson: Yes, if the failing code is included in a TRY/CATCH block, "caught error" is the correct trigger to find the line causing the error.
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!