matrix addition according to position vector

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Rabb
Rabb 2023 年 2 月 6 日
回答済み: Voss 2023 年 2 月 6 日
Hello, i have matrix A wich is 2xn dimension and vector b that is 1xn. I want to sort and sum A acording to vector b. for explamle
A=[1 3 5 7 9 11;
2 4 6 8 10 12]
b=[1 1 3 4 5 3]
so answer would be
C=[4 0 16 7 9
6 0 18 8 10]

採用された回答

Voss
Voss 2023 年 2 月 6 日
A=[1 3 5 7 9 11;
2 4 6 8 10 12];
b=[1 1 3 4 5 3];
Maybe something like this:
C = zeros(size(A));
ub = unique(b);
for ii = 1:numel(ub)
C(:,ub(ii)) = sum(A(:,b == ub(ii)),2);
end
disp(C);
4 0 16 7 9 0 6 0 18 8 10 0
Another way:
[bg,gidx] = findgroups(b);
C = zeros(size(A));
C(:,gidx) = splitapply(@(x)sum(x,2),A,bg);
disp(C);
4 0 16 7 9 0 6 0 18 8 10 0

その他の回答 (1 件)

Vilém Frynta
Vilém Frynta 2023 年 2 月 6 日
This looks like homework.
It seems like you know what kind of functions you should work with. I'd recommend to study the documention of these functions and try to think it out. Feel free to share your progress.
If you are beginning with Matlab, it's good idea just to try (and learn from mistakes and experiments).

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