Integrating acceleration to get the displacement

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Basem Deeb
Basem Deeb 2023 年 2 月 1 日
回答済み: Oskar Kilgus 2023 年 7 月 6 日
Hey
I am trying to integrate acceleration to get the displacement as you can see in the figure below. However, the velocity and displacement are showing exponential decrease. I have used you cumtrapz twice to get the displacement. Anybody know what's the issue here? I also don't want to use detrend to remove the polynomial part,
  3 件のコメント
Sulaymon Eshkabilov
Sulaymon Eshkabilov 2023 年 2 月 2 日
Can you share your numerical data to verify what you have showed here is accurate or not?
Sam Chak
Sam Chak 2023 年 2 月 2 日
Just want to add that in motion system, when performing the integrations, the initial velocity and the initial displacement are required to obtain an accurate solution. From your images, it appears that you assumed and .

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回答 (2 件)

Ganapathi Subramanian
Ganapathi Subramanian 2023 年 4 月 26 日
Hi Basem,
It is my understanding that you are trying to integrate acceleration to obtain velocity and displacement using cumtrapz function. The velocity and displacement graph looks fine. It looks as exponentially decreasing because the acceleration graph is predominantly negative.
You can also add a high pass filter to the acceleration data for baseline correction. But be careful in selecting cut off frequency as higher value leads to loss in valuable information from data.
You can also refer the below file exchange to convert acceleration to velocity and displacement.

Oskar Kilgus
Oskar Kilgus 2023 年 7 月 6 日
Hi Basem,
if you are sure that the displacement is not meaningfull (because you know the properties of the physical system observed), i would suggest to have a look into the frequency domain. Maybe you could work with a highpass filter to "detrend" your data from low-frequency disturbances as these may cause drifts in integrated signals.

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