Why do I get "Array indices must be positive integers or logical values" error?

3 ビュー (過去 30 日間)
Arif Najmi
Arif Najmi 2023 年 1 月 30 日
回答済み: Askic V 2023 年 1 月 30 日
lc= 0.03
b=0.013
Rc= 0.0275
theta1= 0:15:360
theta2=theta1*pi/180
x=lc/2;
y=((Rc^2)*(theta2))
z=((b^2)*0.5)*(sin((theta1).*2))
r=b*(sin(theta1))
u1=Rc^2
u2=r.^2
u=r.*(((u1)-(u2)).^1/2)
rr=Rc^2*atan(r/u)
Vc=x(y+z-u-rr)
Why can't solve? Can someone help me?

回答 (2 件)

Arif Hoq
Arif Hoq 2023 年 1 月 30 日
try this:
lc= 0.03;
b=0.013;
Rc= 0.0275;
theta1= 0:15:360;
theta2=theta1*pi/180;
x=lc/2;
y=((Rc^2)*(theta2));
z=((b^2)*0.5)*(sin((theta1).*2));
r=b*(sin(theta1));
u1=Rc^2;
u2=r.^2;
u=r.*(((u1)-(u2)).^1/2);
rr=Rc^2*atan(r/u);
Vc=x*(y+z-u-rr)
Vc = 1×25
1.0e-04 * -0.1782 -0.1614 -0.1220 -0.0783 -0.0518 -0.0384 -0.0107 0.0362 0.0710 0.0868 0.1066 0.1463 0.1909 0.2132 0.2268 0.2592 0.3043 0.3381 0.3521 0.3732 0.4169 0.4576 0.4786 0.4937 0.5271

Askic V
Askic V 2023 年 1 月 30 日
You asked why, and the answer is because of this line:
Vc=x(y+z-u-rr)
here, x is considered an array and y+z-u-rr is an index. basically you're trying to access an element of the array throught its index. Indices should be positive integers or logical values and not numbers with decimal points.
So this is probably a typo and Arif corrected this line to be:
Vc=x*(y+z-u-rr)

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