Logical operator not evaluating correctly

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Andrew
Andrew 2023 年 1 月 26 日
回答済み: Star Strider 2023 年 1 月 26 日
Given the provided array X, create an array Y that is:
equal to 0 if the corresponding element of X is between -5 and +5, inclusive
equal to -1 if the corresponding element of X is less than -5
equalt to +1 if the corresponding element of X is greater than 5
Here is what I have:
Y = (~(X >= -5 & X <= 5) | (-1*(X < -5)) | (X>5)).
Why is the X < -5 not evaluationg to -1?

採用された回答

Star Strider
Star Strider 2023 年 1 月 26 日
Only two comparisons are actually required here —
X = linspace(-7, 7, 15);
Y = -(X < -5) + (X > 5);
Check_Result = [X; Y]
Check_Result = 2×15
-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 -1 -1 0 0 0 0 0 0 0 0 0 0 0 1 1
.

その他の回答 (2 件)

Walter Roberson
Walter Roberson 2023 年 1 月 26 日
A|B is an or test and returns a logical value -1 is nonzero which is considered true, and since you or everything together you are going to end up with logical true for those entries.
Try adding the results of the computation

Les Beckham
Les Beckham 2023 年 1 月 26 日
I would do this in separate steps.
X = randi([-20, 20], [1 15])
X = 1×15
3 -6 2 6 -7 -8 -7 13 17 -3 5 -13 -17 5 -1
Y = zeros(size(X));
Y(X < -5) = -1;
Y(X > 5) = 1
Y = 1×15
0 -1 0 1 -1 -1 -1 1 1 0 0 -1 -1 0 0

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