I want to rotate the properties fromi=201:600(x) and J=201:600.(Y) That is the properties inside the area inside this area should be rotated. Can someone please help me?

1 回表示 (過去 30 日間)
fid = fopen('moduli','r')
data = fread(fid, inf, 'single', 'ieee-be');
fclose(fid)
data = reshape(data,[800 800 3]);
for i=201,600
for j=201,600
end
end
figure(1)
pcolor(data(:,:,1))
axis tight;
shading interp;
colorbar;
set(gcf,'renderer','zbuffer')
print -dpng mod
  2 件のコメント
Image Analyst
Image Analyst 2023 年 1 月 21 日
YOu forgot to attach the 'moduli' file. And how can a property be rotated?
Vishnu Vannarath Rajan
Vishnu Vannarath Rajan 2023 年 1 月 21 日
Thank you so much for the reply. I meant to rotate the area mentioned. Some properties are assigned inside this area and the properties will automatically be re-assigned if it has been rotated. Hereby attaching the compressed version of moduli.

サインインしてコメントする。

回答 (1 件)

Nehemiae
Nehemiae 2023 年 3 月 10 日
Hello,
To rotate to rotate the submatrix of data, the “imrotate” function can be used. In the example below, the rotation is limited to the region of interest with the surrounding areas being set as 0, and the extruding areas being cropped. However, this can be configured by the “imrotate” options as per the requirement.
data(201 : 600, 201 : 600, 1) = imrotate(data(201 : 600, 201 : 600, 1), 45, "bilinear", "crop");
The documentation on the “imrotate” function (https://www.mathworks.com/help/images/ref/imrotate.html) is helpful in this regard.

カテゴリ

Help Center および File Exchange2-D and 3-D Plots についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by