I am having two matrix of sizes 7*7 and 7*1. Now, i need to compare both matrix and entries in one matrix varies based on another matrix. For example, element in fourth row first column of matrix A is 1 and element in first row of matrix B is, so, expected output at matrix C is element 1 in fourth row of first column, whereas remaining terms are 0. Similarly, element in first row of fourth column is 1 in matrix A and fourth entry of matrix B is 0, so output matrix C has 0 element in first row of fourth column. Thank you in advance.
Example:
A=[0 0 0 1 0 0 0
0 1 0 0 0 0 0
0 0 0 0 1 0 0
1 0 0 0 0 0 0
0 0 0 0 0 1 0
0 0 1 0 0 0 0
0 0 0 0 0 0 1]
B=[1; 1; 0; 0; 1; 0; 1]
Expected output:
C=[0 0 0 0 0 0 0
0 1 0 0 0 0 0
0 0 0 0 1 0 0
1 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 1]

 採用された回答

Voss
Voss 2023 年 1 月 2 日
編集済み: Voss 2023 年 1 月 2 日

0 投票

One way:
A=[0 0 0 1 0 0 0
0 1 0 0 0 0 0
0 0 0 0 1 0 0
1 0 0 0 0 0 0
0 0 0 0 0 1 0
0 0 1 0 0 0 0
0 0 0 0 0 0 1];
B=[1; 1; 0; 0; 1; 0; 1];
C = zeros(size(A));
idx = logical(B);
C(:,idx) = A(:,idx)
C = 7×7
0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1

2 件のコメント

ASHA PON
ASHA PON 2023 年 1 月 2 日
Thank you for the answer. This is what i needed.
Voss
Voss 2023 年 1 月 2 日
You're welcome!

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