フィルターのクリア

How can I make the random point moves based on locations ?

1 回表示 (過去 30 日間)
omar th
omar th 2022 年 12 月 29 日
回答済み: Image Analyst 2022 年 12 月 30 日
Below there is a point randomly deployed, its moved based on the angles which leads to generate or deply that point in 5 locations according to the number of angles. My question how can I store these 5 positions in a matrix OR can I make index 5 positions in order to move that random point based on position ?? NOTE: The 5 positions that I'm asking about are " newPos " that mentioned in the code below.
Thanks in advance and appreciate any comment
%pointPos = [0 0];
v=2;%7.2/3.6;
%x=plot(pointPos,'*');
NumDrone1=1;center=[0 0];ro1=1000;
theta_Drone1=2*pi*(rand(NumDrone1,1));
g1 = 0.1 * ro1 + 0.1 * ro1 * rand(NumDrone1,1);
PosPoint1_x=center(1)+g1.*cos(theta_Drone1); % Initial positions
PosPoint1_y=center(2)+g1.*sin(theta_Drone1);
PosPoint1 = [PosPoint1_x ,PosPoint1_y]
hfig = figure('Color', 'w');
hax = axes('Parent', hfig);
h(1) = plot(PosPoint1(1,1),PosPoint1(1,2),'Parent', hax,'Marker', '.','Color', 'k','LineStyle', '-','MarkerSize', 12);
hold(hax, 'on')
grid(hax, 'on')
axis(hax, 'equal')
angleOption = [24 56 72 36 96]
for ii = 1:numel(angleOption)
chooseAngle = angleOption(ii)
displacement = [cos(chooseAngle).*v, sin(chooseAngle).*v];
newPos = PosPoint1 + displacement
startpos = newPos-displacement
XData = [h.XData newPos(:, 1)];
YData = [h.YData newPos(:, 2)];
set(h, 'XData', XData, 'YData', YData)
drawnow
XData = [h.XData startpos(:, 1)];
YData = [h.YData startpos(:, 2)];
set(h, 'XData', XData, 'YData', YData)
drawnow
end

回答 (1 件)

Image Analyst
Image Analyst 2022 年 12 月 30 日
I didn't dig in to your code but it sounds like you want to do a random walk.
See my collection of random walk demos.
To store values in an array you need to index them with the loop counter, like
XData(ii) = newPos(:, 1);
YData(ii) = newPos(:, 2);
and don't do that second set of assignments to XData and YData.

カテゴリ

Help Center および File ExchangeProgramming についてさらに検索

製品


リリース

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by