Error using indexing Invalid indexing or function definition. Indexing must follow MATLAB indexing.

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TEOH CHEE JIN
TEOH CHEE JIN 2022 年 12 月 27 日
回答済み: VBBV 2022 年 12 月 27 日
I encounter "Error using indexing
Invalid indexing or function definition. Indexing must follow MATLAB indexing. Function arguments must be symbolic
variables, and function body must be sym expression.
Error in modified_signal (line 54)
B(w) = fourier(b(t), w);" with this script when using symbolic function, the signal A(w), a(t), and b(t) do not have any issue, but B(w) has caused the error. Any solution to overcome this issue? Thank you.
%create symbolic functions x, a, b, c, d, e, f_c with independent variable t
syms x(t) a(t) h(t) b(t) c(t) d(t) e f_c(t) f_c1(t) f_c2(t) t tau
%create symbolic functions A, B, C, D, and E with independent variable w
syms A(w) B(w) C(w) D(w) E(w) w
x(t) = cos(100*pi*t);
a(t) = x(0.4*t);
h(t) = dirac(t-0.02);
b(t) = int(a(tau)*h(t-tau), 'tau', -inf, inf);
f_c(t) = 10*cos(2500*pi*t);
f_c1(t) = f_c(t);
f_c2(t) = f_c(t);
c(t) = b(t)*f_c1(t);
d(t) = c(t)*f_c2(t);
figure
subplot (2,1,1)
fplot(a(t))
xlim([-0.05 0.05]),ylim([-1.5 1.5])
title ('Time domain of signal a(t)')
xlabel('Time, t')
ylabel('Amplitude, a(t)')
grid on
A(w) = fourier(a(t), w);
w = -60*pi:0.1*pi:60*pi;
subsA = A(w);
% Replace Inf value with suitable value
idx = subsA == Inf;
subsA(idx) = pi; % choose suitable value from the expression of fourier transform.
subplot (2,1,2)
plot(w,real(subsA));
ylim([0 3.5])
title ('Time domain of signal A(\omega)')
ylabel("\Re(A(\omega))");
xlabel("\omega");
xticks(-40*pi:20*pi:40*pi);
xticklabels({'-40\pi', '-20\pi', '0', '20\pi', '40\pi'})
figure
subplot(2,1,1)
fplot(b(t))
xlim([-0.05 0.05]),ylim([-1.5 1.5])
title ('Time domain of signal b(t)')
xlabel('Time, t')
ylabel('Amplitude, b(t)')
grid on
B(w) = fourier(b(t), w);
Error using indexing
Invalid indexing or function definition. Indexing must follow MATLAB indexing. Function arguments must be symbolic variables, and function body must be sym expression.
w = -60*pi:0.1*pi:60*pi;
subsB = B(w);
% Replace Inf value with suitable value
idx = abs(subsB) == Inf;
subsB(idx) = pi; % choose suitable value from the expression of fourier transform.
subplot (2,1,2)
plot(w,real(subsB));
ylim([0 3.5])
title ('Time domain of signal B(\omega)')
ylabel("\Re(B(\omega))");
xlabel("\omega");
xticks(-40*pi:20*pi:40*pi);
xticklabels({'-40\pi', '-20\pi', '0', '20\pi', '40\pi'})
figure
subplot(2,1,1)
fplot(c(t))
xlim([-0.05 0.05]),ylim([-12 12])
title ('Time domain of signal c(t)')
xlabel('Time, t')
ylabel('Amplitude, c(t)')
grid on
figure
subplot(2,1,1)
fplot(d(t))
xlim([-0.1 0.1]),ylim([-110 110])
title ('Time domain of signal d(t)')
xlabel('Time, t')
ylabel('Amplitude, d(t)')
grid on

回答 (1 件)

VBBV
VBBV 2022 年 12 月 27 日
%create symbolic functions x, a, b, c, d, e, f_c with independent variable t
syms x(t) a(t) h(t) b(t) c(t) d(t) e f_c(t) f_c1(t) f_c2(t) t tau
%create symbolic functions A, B, C, D, and E with independent variable w
syms A(w) B(w) C(w) D(w) E(w) w
x(t) = cos(100*pi*t);
a(t) = x(0.4*t);
h(t) = dirac(t-0.02);
b(t) = int(a(tau)*h(t-tau), 'tau', -inf, inf)
b(t) = 
f_c(t) = 10*cos(2500*pi*t);
f_c1(t) = f_c(t);
f_c2(t) = f_c(t);
c(t) = b(t)*f_c1(t);
d(t) = c(t)*f_c2(t);
figure
subplot (2,1,1)
fplot(a(t))
xlim([-0.05 0.05]),ylim([-1.5 1.5])
title ('Time domain of signal a(t)')
xlabel('Time, t')
ylabel('Amplitude, a(t)')
grid on
A(w) = fourier(a(t), w);
w = -60*pi:0.1*pi:60*pi;
subsA = A(w);
% Replace Inf value with suitable value
idx = subsA == Inf;
subsA(idx) = pi; % choose suitable value from the expression of fourier transform.
subplot (2,1,2)
plot(w,real(subsA));
ylim([0 3.5])
title ('Time domain of signal A(\omega)')
ylabel("\Re(A(\omega))");
xlabel("\omega");
xticks(-40*pi:20*pi:40*pi);
xticklabels({'-40\pi', '-20\pi', '0', '20\pi', '40\pi'})
figure
subplot(2,1,1)
fplot(b(t))
xlim([-0.05 0.05]),ylim([-1.5 1.5])
title ('Time domain of signal b(t)')
xlabel('Time, t')
ylabel('Amplitude, b(t)')
grid on
syms w
B(w) = fourier(b(t), w);
w = -60*pi:0.1*pi:60*pi;
subsB = B(w);
% Replace Inf value with suitable value
idx = abs(subsB) == Inf;
subsB(idx) = pi; % choose suitable value from the expression of fourier transform.
subplot (2,1,2)
plot(w,real(subsB));
ylim([0 3.5])
title ('Time domain of signal B(\omega)')
ylabel("\Re(B(\omega))");
xlabel("\omega");
xticks(-40*pi:20*pi:40*pi);
xticklabels({'-40\pi', '-20\pi', '0', '20\pi', '40\pi'})
figure
subplot(2,1,1)
fplot(c(t))
xlim([-0.05 0.05]),ylim([-12 12])
title ('Time domain of signal c(t)')
xlabel('Time, t')
ylabel('Amplitude, c(t)')
grid on
figure
subplot(2,1,1)
fplot(d(t))
xlim([-0.1 0.1]),ylim([-110 110])
title ('Time domain of signal d(t)')
xlabel('Time, t')
ylabel('Amplitude, d(t)')
grid on

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