how to do loop on rows matrix?
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i have zeros matrix which has 3 rows and 6 columns. i want to allocate “1” on zeros matrix for each columns in order to get the result output like this attached picture. can anyone be kind to help me? thanks in advance
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VBBV
2022 年 12 月 23 日
編集済み: VBBV
2022 年 12 月 23 日
As mentioned in your question, if you have zeros matrix to start with and want to allocate 1s to specfiic zero locations, then you can get the matrix in snapshot using loop as below
A = zeros(3,6); % assume A as your zeros matrix
for k = 1:length(A)-2
if k == 1 | k == 2 | k == 3
A(k,k) = 1;
elseif k == 4
A(1,k) = 1;
A(2,k+1) = 1;
A(3,k+2) = 1;
end
end
A
2 件のコメント
VBBV
2022 年 12 月 23 日
It depends on how you want final matrix to look like. That is "in which specific positions you want to allocate 1s in zero matrix"
その他の回答 (2 件)
Image Analyst
2022 年 12 月 26 日
% For 3x6:
c = [1 0 0 1 0 0];
r = [1 0 0];
output = toeplitz(r, c)
% For 15 by 25
c = [1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1];
r = [1; zeros(15, 1)];
output = toeplitz(r, c)
3 件のコメント
Image Analyst
2022 年 12 月 27 日
@Risma Fitriyani did you not like my answer for the 15x25? Does the answer you accepted work?
Again, can you give the full output for your 15x25 matrix like @Markus M. directly asked you for? I'd like to see how my solution does not do what you want.
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