Position error of motor shaft

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saleh shlimet
saleh shlimet 2022 年 12 月 13 日
コメント済み: Mathieu NOE 2022 年 12 月 20 日
I want to obtain the position error of motor shaft so I subtracted the estimated position from the measured position. modulus function is used so the estimated and the measured positions vary between 0 to 2pi (electrical radians) as shown in the figures attached. the problem is that the error becomes 2pi at instant times. What can I do to not show this big error (2pi) in the figure?

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Mathieu NOE
Mathieu NOE 2022 年 12 月 13 日
移動済み: Joel Van Sickel 2022 年 12 月 15 日
hello
you can make 2 pi complements on the error signal , following that logic
if error < -pi then error = error + 2pi
if error > pi then error = error - 2pi
goal is to keep error witin -pi / + pi bounds
  13 件のコメント
saleh shlimet
saleh shlimet 2022 年 12 月 19 日
Thank you very much Mathieu it is working properly.
Mathieu NOE
Mathieu NOE 2022 年 12 月 20 日
My pleasure !

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