How can I set the values of matrix in interval <a, b>?

19 ビュー (過去 30 日間)
Ihor
Ihor 2022 年 12 月 4 日
コメント済み: DGM 2022 年 12 月 4 日
Generate a matrix Ru of pseudo-random floating point values from a uniform distribution, a matrix Ri of pseudo- random integer
values from a uniform distribution and a matrix Rn of pseudo-random values from a normal distribution. Let the size of all
matrices be M x N. Let the expected value of Rn be m = 8 and variance v = 3. Let the values of Ru an Ri be from the interval < a,
b > = < 4, 9 >.
Rn = rand( M, N ) ;
Ru = randn( M, N) ;
Ri = randi( [a, b], M, N ) ; % here I know how to set the interval <a, b>
  2 件のコメント
Stephen23
Stephen23 2022 年 12 月 4 日
編集済み: Stephen23 2022 年 12 月 4 日
Original question by Ihor retrieved from Google cache:
How can I set the values of matrix in interval <a, b>?
Generate a matrix Ru of pseudo-random floating point values from a uniform distribution, a matrix Ri of pseudo- random integer
values from a uniform distribution and a matrix Rn of pseudo-random values from a normal distribution. Let the size of all
matrices be M x N. Let the expected value of Rn be m = 8 and variance v = 3. Let the values of Ru an Ri be from the interval < a,b > = < 4, 9 >.
Rn = rand( M, N ) ;
Ru = randn( M, N) ;
Ri = randi( [a, b], M, N ) ; % here I know how to set the interval <a, b>
Rik
Rik 2022 年 12 月 4 日
I recovered the removed content from the Google cache (something which anyone can do). Editing away your question is very rude. Someone spent time reading your question, understanding your issue, figuring out the solution, and writing an answer. Now you repay that kindness by ensuring that the next person with a similar question can't benefit from this answer.

サインインしてコメントする。

採用された回答

DGM
DGM 2022 年 12 月 4 日
編集済み: DGM 2022 年 12 月 4 日
Start with:
m = 500;
n = 500;
rrange = [4 9];
mn = 8;
vr = 3;
% uniform distribution with a specified range
Ru = rrange(1) + range(rrange)*rand(m,n);
[min(Ru(:)) max(Ru(:))]
ans = 1×2
4.0000 9.0000
% normal distribution with specified mean, variance
Rn = mn + sqrt(vr)*randn(m,n);
[mean(Rn(:)) var(Rn(:))]
ans = 1×2
7.9939 3.0058
% discrete uniform random integers
Ri = randi(rrange,m,n);
[min(Ri(:)) max(Ri(:))]
ans = 1×2
4 9
  3 件のコメント
Ihor
Ihor 2022 年 12 月 4 日
Is there tha way in which I can change the range() function because of it in other ToolBox?
DGM
DGM 2022 年 12 月 4 日
oof. I forgot that was in stats toolbox.
Ru = rrange(1) + (rrange(2)-rrange(1))*rand(m,n);

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeRandom Number Generation についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by