How to multiply each term in a n*n matrix with elements in a column matrix
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I am having a 14*15 matrix and 15*1 matrix. Now, I need to multiply these two matrix. Thank you in advance.
For example:
A=[ 0.34005, 1.15985, -1.42862; 0.45204, -0.12963, -0.07851; 0.18586, -0.49792, 0.56187; 0.20188, 0.19786, -0.54699]
B=[0; 0; 1; 1]
Expected output:
A11 - First row first column, A21 - Second row first column
C=[A11*B2, A21*B3, A31*B4; A12*B1, A22*B3, A32*B4; A13*B1, A23*B2, A33*B4; A14*B1, A24*B2, A34*B3]
C=[0, 1.15985, -1.42862; 0, -0.12963, -0.07851; 0, 0, 0.56187; 0, 0, -0.54699]
3 件のコメント
John D'Errico
2022 年 12 月 1 日
Confusing. You seem to be mixing up rows and columns, sort of randomly. In your words, you talk about a matrix with 14 rows and 15 columns. But your example has more rows than columns in A. But then the way you then show the indexes for A, it has more columns than rows. Perhaps you don't understand how MATLAB treats arrays.
A = reshape(1:12,4,3)
A is a 4x3 matrix. It has 4 rows, and 3 columns. The FIRST index of A is the row number. The second index refers to the column number. So in MATLAB for this matrix, A(1,2) == 5.
回答 (1 件)
KSSV
2022 年 12 月 1 日
A=[ 0.34005, 1.15985, -1.42862; 0.45204, -0.12963, -0.07851; 0.18586, -0.49792, 0.56187; 0.20188, 0.19786, -0.54699] ;
B=[0; 0; 1; 1] ;
% A11 - First row first column, A21 - Second row first column
% C=[A11*B2, A21*B3, A31*B4; A12*B1, A22*B3, A32*B4; A13*B1, A23*B2, A33*B4; A14*B1, A24*B2, A34*B3]
C=[0, 1.15985, -1.42862; 0, -0.12963, -0.07851; 0, 0, 0.56187; 0, 0, -0.54699] ;
b = zeros(length(B)-1) ;
for i = 1:length(B)-1
t = B' ;
t(i) =[] ;
b(i,:) = t ;
end
iwant = A*b
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