Rearranging matrix of sth elements

1 回表示 (過去 30 日間)
maria
maria 2022 年 11 月 30 日
回答済み: David Hill 2022 年 11 月 30 日
Dear community,
I have a 1x1716 array that I would like to rearrange but I also would like to keep the 1x1716 matrix shape. I need to take a cell every 66th position and after finishing going on starting in position 2 and then 67 (1+66),133,199, etc... and continue with position 3, 68,134,200, etc... Could you help me?
I can write an example with a simpler matrix arranged every 3rd position instead of 66:
A=[1 2 3 4 5 6 7 8 9 10]
B=[1 4 7 10 2 5 8 3 6 9]

採用された回答

David Hill
David Hill 2022 年 11 月 30 日
n=1:1716;
N=[];
for k=1:66
N=[N,n(k:66:end)];
end

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMultidimensional Arrays についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by