Normalizing a set of data to zero
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Data Attempting to clear:
Code:
%% Normalizing Step (2):IPS Direct Relationship
b_min = ( 1 ./ (quantile(peaks_b,1)))*1000;
IPS_norm_b = (1 ./ IPS_clean_b) *1000 ;
IPS_b = (IPS_norm_b - b_min) ;
IPS_data = IPS_b;
figure
plot(IPS_b)
title("IPS_normal_b")
%% Normalizing Step (3): Subtracting min values (step 2 repeat but in direct form)
x = 1: (length(IPS_b));
max2 = max(IPS_b)
max_minlimit3 = max2*.75;
[ TF3, P] = islocalmax(IPS_b, 'MinProminence', max_minlimit3);
% [ TF3, P] = islocalmin(IPS_data,'FlatSelection', 'all');
figure
plot(x,IPS_b,x(TF3),IPS_b(TF3),'r*')
title("IPS_b1")
IPS_min = mean(P(TF3))
IPS_datanorm = (IPS_b - IPS_min);
figure
plot(IPS_datanorm)
title('normal (3)')
Data After Code:
Hello,
I hope you are doing well. I am reaching out to the community to see if anyone can offer guidence with normalizing by data to zero. Essentionally I'm trying to get the vallies of my curves to bottom our at zero but this is not happening. If you have the time please help me out.
3 件のコメント
Walter Roberson
2022 年 11 月 29 日
It sounds like they would like to subtract min() of the curves so that the shifted minimum becomes zero.
回答 (1 件)
John D'Errico
2022 年 11 月 29 日
編集済み: John D'Errico
2022 年 11 月 29 日
Do you want ALL of those minima to be zero? If so, then you will need to do something especially artful. If all you want is the global min to be zero, then just subtract the min of y.
yNorm = y - min(y);
But my guess is you are looking to somehow shift each local min to be zero. That will be difficult, because it will introduce discontinuities in the curve unless you are particularly careful about how you do it. The point is, your curve would need to be shifted by different amounts, based on how far off it is at that min.
I will not get into how you might do the latter, unless you really wanted some sort of solution there.
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