stacking of large matrix into stack of small column matrix

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Milan
Milan 2022 年 11 月 26 日
回答済み: DGM 2022 年 11 月 26 日
Hello here i want to put row of w matrix as a column vector in w_stack for i as a number of element. i.e each row of w corresponds to each element which i want it a column vector. can you please help me
nele = 8;
w = zeros(nele,3);
w = [0 0 0;
0 0 0;
0 0 0;
0 0 0;
0 0 -2;
0 0 -2;
0 0 -2;
0 0 -2];
w_trans = w';
W = w_trans(:);
w_stack = zeros(3,1,nele);
for i = nele
w_stack(1:3,1,i) = w(1:w(1:3, 1, i)';
end

回答 (1 件)

DGM
DGM 2022 年 11 月 26 日
I'm not really sure what exactly you want, but I'm going to take a guess anyway. I'm going to assume that nele is possibly less than size(w,1). I'm going to interpret your original prototype code as to be:
nele = 8;
w = [0 0 0;
0 0 0;
0 0 0;
0 0 0;
0 0 -2;
0 0 -2;
0 0 -2;
0 0 -2];
w_stack = zeros(3,1,nele);
for i = 1:nele
w_stack(:,1,i) = w(i,:);
end
w_stack
w_stack =
w_stack(:,:,1) = 0 0 0 w_stack(:,:,2) = 0 0 0 w_stack(:,:,3) = 0 0 0 w_stack(:,:,4) = 0 0 0 w_stack(:,:,5) = 0 0 -2 w_stack(:,:,6) = 0 0 -2 w_stack(:,:,7) = 0 0 -2 w_stack(:,:,8) = 0 0 -2
If that's a correct interpretation of your goal, then you can replace that with one line:
wstack = permute(w(1:nele,:),[2 3 1])
wstack =
wstack(:,:,1) = 0 0 0 wstack(:,:,2) = 0 0 0 wstack(:,:,3) = 0 0 0 wstack(:,:,4) = 0 0 0 wstack(:,:,5) = 0 0 -2 wstack(:,:,6) = 0 0 -2 wstack(:,:,7) = 0 0 -2 wstack(:,:,8) = 0 0 -2
... and the results are the same.

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