Array assembly by indexing in a loop

I have the following code:

n = 4; 
x1 = linspace(0,2,n);
y1_x1 = sqrt(1-( (x1.^2)/4 ) );
Y1_X1 = []
for i = 1:n
    Y1_X1(end) = y1_x1(i:end);
end

The idea is to form Y1_X1 such that first time, it takes n values of y1_x1 (in this case all 4), next time it takes (n-1):end values of y1_x1 (in this case last 3) and assembles these 3 infront of the first 4, and does this all the way till it gets the last value in y1_x1 and assembles it at the end of the long Y1_X1. So output of loop looks like this:

Y1_X1 =

    1.0000    0.9428    0.7454         0    0.9428    0.7454         0    0.7454         0         0

Thanks

Answer 1

[Bruno Luong]

n = 4; 
x1 = linspace(0,2,n);
y1_x1 = sqrt(1-( (x1.^2)/4 ) );
Y1_X1 = [];
for i = 1:n
    Y1_X1 =  [Y1_X1, y1_x1(i:end)]; % concatenate
end
Y1_X1

Y1_X1 = 1×10

1.0000 0.9428 0.7454 0 0.9428 0.7454 0 0.7454 0 0

[Saim Ehtesham]

Thanks