problem with condtitions in program

Hello I have the following problem. I would like my program to subtract data from t1 from t. The purpose of my program is to assume that the values will be in a given range from 0.1900 to 0.2600. If the program subtracts the value of t1-t it receives a value in the given range then it is supposed to write this value into a variable. If, on the other hand, it does not receive a given value because, for example, there is a value of 68 the next one is only 88 and you can see that there is a lack of samples here. The program has to subtract more data from the vector until it receives the required value. The problem I have is that when I enter only one boundary value the program works, but when I want to enter a second one unfortunately the program does not work properly.

t=[0.0840000000000000,0.935000000000000,1.83900000000000,2.85400000000000,3.84500000000000,4.73200000000000,5.71000000000000,6.77900000000000,7.75000000000000,8.62400000000000,9.40900000000000,10.1720000000000,10.9430000000000,11.8060000000000,12.6770000000000,13.8250000000000,14.9320000000000,16.0030000000000,17.0310000000000,17.9190000000000,18.6890000000000,19.4270000000000,20.2120000000000,21.1040000000000,22.0370000000000,22.9860000000000,23.9090000000000,24.7900000000000,25.6760000000000,26.5840000000000,27.4870000000000,28.4060000000000,29.3130000000000,30.1520000000000,30.9750000000000,31.8760000000000,32.8330000000000,33.7180000000000,34.6020000000000,35.5970000000000,36.6070000000000,37.5170000000000,38.4710000000000,39.4750000000000,40.3770000000000,41.2570000000000,42.2520000000000,43.2800000000000,44.2160000000000,45.1490000000000,46.1790000000000,47.2260000000000,48.1870000000000,49.1360000000000,50.2220000000000,51.3240000000000,52.3400000000000,53.2800000000000,54.2750000000000,55.4050000000000,56.5300000000000,57.5530000000000,58.5850000000000,59.6640000000000,60.6640000000000,61.6140000000000,62.7610000000000,63.8230000000000,64.8040000000000,65.9080000000000,67.0560000000000,68.0810000000000,69.1380000000000,70.2060000000000,71.1900000000000,72.2370000000000,73.3250000000000,74.3050000000000,75.3310000000000,76.4380000000000,77.4460000000000,78.4250000000000,79.4900000000000,80.5880000000000,81.5760000000000,82.6540000000000,83.7080000000000,84.6390000000000,85.6360000000000,86.7050000000000,87.7210000000000,88.6310000000000,89.6890000000000,90.7540000000000,91.7460000000000,92.7570000000000,93.8380000000000,94.8490000000000,95.7690000000000,96.8210000000000]

t1=[0.196000000000000,1.13900000000000,2.03600000000000,3.04600000000000,4.04900000000000,4.93400000000000,5.90100000000000,6.97500000000000,7.95300000000000,8.83400000000000,9.61600000000000,10.3740000000000,11.1410000000000,12.0020000000000,12.8700000000000,14.0140000000000,15.1210000000000,16.1940000000000,17.2230000000000,18.1150000000000,18.8850000000000,19.6220000000000,20.4060000000000,21.2920000000000,22.2280000000000,23.1800000000000,24.1070000000000,24.9870000000000,25.8710000000000,26.7790000000000,27.6820000000000,28.6010000000000,29.5120000000000,30.3530000000000,31.1680000000000,32.0640000000000,33.0270000000000,33.9180000000000,34.7930000000000,35.7840000000000,36.8060000000000,37.7130000000000,38.6610000000000,39.6720000000000,40.5790000000000,41.4500000000000,42.4420000000000,43.4790000000000,44.4190000000000,45.3440000000000,46.3700000000000,47.4230000000000,48.3910000000000,49.3320000000000,50.4140000000000,51.5180000000000,52.5440000000000,53.4820000000000,54.4680000000000,55.5970000000000,56.7320000000000,57.7540000000000,58.7790000000000,59.8600000000000,60.8690000000000,61.8090000000000,62.9540000000000,64.0280000000000,65.0040000000000,66.1040000000000,67.2660000000000,68.3030000000000,NaN,NaN,88.0120000000000,88.9140000000000,89.9530000000000,91.0270000000000,92.0150000000000,93.0150000000000,94.0890000000000,95.1110000000000,96.0140000000000,97.0600000000000]

indexA = 1;

indexB =1;

for indexB = 1:length(t1)

c=t1(indexB)-t(indexA);

if (c<0.2600)&&(c<0.1900)

disp(t(indexA))

disp(t1(indexB))

d(indexB)=c;

disp('----------')

else

indexA=indexA+1;

c=t1(indexB)-t(indexA);

while (c>0.2600)&&(c>0.1900)

indexA=indexA+1;

c=t1(indexB)-t(indexA);

d(indexB)=c;

end

disp(t(indexA))

disp(t1(indexB))

d(indexB)=c;

disp('----------')

end

end

[Chandler Hall]

What is the source of t and t1? They are different lengths. Would it not be more appropriate to ensure they are the same length and then check the value of t1(i) - t(i)? What is the ultimate purpose of d?

[Krystian Sliwka]

any idea to make them the same size ?

The purpose of d is to display the results on a graph. They should be within a given range

Answer 1

[David Hill]

Hard to understand what you are trying to do. Looks like you are good to about 72.

t=[0.0840000000000000,0.935000000000000,1.83900000000000,2.85400000000000,3.84500000000000,4.73200000000000,5.71000000000000,6.77900000000000,7.75000000000000,8.62400000000000,9.40900000000000,10.1720000000000,10.9430000000000,11.8060000000000,12.6770000000000,13.8250000000000,14.9320000000000,16.0030000000000,17.0310000000000,17.9190000000000,18.6890000000000,19.4270000000000,20.2120000000000,21.1040000000000,22.0370000000000,22.9860000000000,23.9090000000000,24.7900000000000,25.6760000000000,26.5840000000000,27.4870000000000,28.4060000000000,29.3130000000000,30.1520000000000,30.9750000000000,31.8760000000000,32.8330000000000,33.7180000000000,34.6020000000000,35.5970000000000,36.6070000000000,37.5170000000000,38.4710000000000,39.4750000000000,40.3770000000000,41.2570000000000,42.2520000000000,43.2800000000000,44.2160000000000,45.1490000000000,46.1790000000000,47.2260000000000,48.1870000000000,49.1360000000000,50.2220000000000,51.3240000000000,52.3400000000000,53.2800000000000,54.2750000000000,55.4050000000000,56.5300000000000,57.5530000000000,58.5850000000000,59.6640000000000,60.6640000000000,61.6140000000000,62.7610000000000,63.8230000000000,64.8040000000000,65.9080000000000,67.0560000000000,68.0810000000000,69.1380000000000,70.2060000000000,71.1900000000000,72.2370000000000,73.3250000000000,74.3050000000000,75.3310000000000,76.4380000000000,77.4460000000000,78.4250000000000,79.4900000000000,80.5880000000000,81.5760000000000,82.6540000000000,83.7080000000000,84.6390000000000,85.6360000000000,86.7050000000000,87.7210000000000,88.6310000000000,89.6890000000000,90.7540000000000,91.7460000000000,92.7570000000000,93.8380000000000,94.8490000000000,95.7690000000000,96.8210000000000];
t1=[0.196000000000000,1.13900000000000,2.03600000000000,3.04600000000000,4.04900000000000,4.93400000000000,5.90100000000000,6.97500000000000,7.95300000000000,8.83400000000000,9.61600000000000,10.3740000000000,11.1410000000000,12.0020000000000,12.8700000000000,14.0140000000000,15.1210000000000,16.1940000000000,17.2230000000000,18.1150000000000,18.8850000000000,19.6220000000000,20.4060000000000,21.2920000000000,22.2280000000000,23.1800000000000,24.1070000000000,24.9870000000000,25.8710000000000,26.7790000000000,27.6820000000000,28.6010000000000,29.5120000000000,30.3530000000000,31.1680000000000,32.0640000000000,33.0270000000000,33.9180000000000,34.7930000000000,35.7840000000000,36.8060000000000,37.7130000000000,38.6610000000000,39.6720000000000,40.5790000000000,41.4500000000000,42.4420000000000,43.4790000000000,44.4190000000000,45.3440000000000,46.3700000000000,47.4230000000000,48.3910000000000,49.3320000000000,50.4140000000000,51.5180000000000,52.5440000000000,53.4820000000000,54.4680000000000,55.5970000000000,56.7320000000000,57.7540000000000,58.7790000000000,59.8600000000000,60.8690000000000,61.8090000000000,62.9540000000000,64.0280000000000,65.0040000000000,66.1040000000000,67.2660000000000,68.3030000000000,NaN,NaN,88.0120000000000,88.9140000000000,89.9530000000000,91.0270000000000,92.0150000000000,93.0150000000000,94.0890000000000,95.1110000000000,96.0140000000000,97.0600000000000];
a=t1(1:72)-t(1:72)

a = 1×72

0.1120 0.2040 0.1970 0.1920 0.2040 0.2020 0.1910 0.1960 0.2030 0.2100 0.2070 0.2020 0.1980 0.1960 0.1930 0.1890 0.1890 0.1910 0.1920 0.1960 0.1960 0.1950 0.1940 0.1880 0.1910 0.1940 0.1980 0.1970 0.1950 0.1950

b=a(a>=.19&a<=.26)%a few are not in the range, do not know what you want to do if they are not in the range

b = 1×65

0.2040 0.1970 0.1920 0.2040 0.2020 0.1910 0.1960 0.2030 0.2100 0.2070 0.2020 0.1980 0.1960 0.1930 0.1910 0.1920 0.1960 0.1960 0.1950 0.1940 0.1910 0.1940 0.1980 0.1970 0.1950 0.1950 0.1950 0.1950 0.1990 0.2010

[Krystian Sliwka]

Look at the vectors t. You can see there the value up to 68 further we have NaN and only the values 88. I want the program to subtract t1-t. If the value in the range doesn't come out we take another sample from the t vector. E.g.

68.303-68.081=0.222

Then we have NaN and then for 88.012 but that corresponds to 71.19.

So that the value is in the range:88.12-87.721=2.91.

Here I noticed that I should increase the range, however.

I want the program to keep adding samples until it gets a value in range.

That is, the while loop probably has the wrong condition

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