Table column of strings to a matrix.

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Daniel
Daniel 2022 年 11 月 14 日
回答済み: Steven Lord 2022 年 11 月 14 日
Hello,
i am beginer and i am struggling with matlab tables. I have a table column that contains strings with vectors inside
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
I would like to have a matrix with the numbers inside, like
B=[0 0 0 0 0 0 0 0;0 0 0 0 0 0 0 0;0 0 0 0 0 0 0 0;1 1 1 1 1 1 1 1]
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
How can i do this without using loops? Thank you in advance.
  2 件のコメント
Stephen23
Stephen23 2022 年 11 月 14 日
編集済み: Stephen23 2022 年 11 月 14 日
"I have a table column that contains strings with vectors inside "
This looks like file importing is suboptimal. You can probably change the file importing to import numeric as numeric, which most likely would be simpler and more efficient than messing around with text like this.
Jan
Jan 2022 年 11 月 14 日
"I have a table column that contains strings with vectors inside" - no, there is no table. This is a column vector of strings. If the strings are interpreted as Matlab, they would be vectors, but they are not "inside".

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採用された回答

Stephen23
Stephen23 2022 年 11 月 14 日
A = ["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
M = cell2mat(cellfun(@str2num,A,'uni',0))
M = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1

その他の回答 (3 件)

RAGHUNATHRAJU DASHARATHA
RAGHUNATHRAJU DASHARATHA 2022 年 11 月 14 日
As per my understanding you want to get a matrix from the string array
I will demonstarte it using the example below
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
B =extract(A,digitsPattern)
B = 4×8 string array
"0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "1" "1" "1" "1" "1" "1" "1" "1"
B=str2double(B)
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
for more information go through the link
  1 件のコメント
Stephen23
Stephen23 2022 年 11 月 14 日
+1 very neat.

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Steven Lord
Steven Lord 2022 年 11 月 14 日
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
A2 = erase(A, ["[", "]"])
A2 = 4×1 string array
"0 0 0 0 0 0 0 0" "0 0 0 0 0 0 0 0" "0 0 0 0 0 0 0 0" "1 1 1 1 1 1 1 1"
double(split(A2, ' '))
ans = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1

Jan
Jan 2022 年 11 月 14 日
編集済み: Jan 2022 年 11 月 14 日
A = ["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"];
AC = char(A);
AC(ismember(AC, '[] ')) = [];
AC = reshape(AC, numel(A), []);
B = AC - '0'
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
Alternative:
AC = char(extract(A, digitsPattern));
B = squeeze(AC) - '0'
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1

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