- What is your use case and the workflow you are following?
- “.mat” and “.m” files you are using to accomplish the above task.
I am using a function 'eye' but i don't need this diagonal to be maximum value
1 回表示 (過去 30 日間)
古いコメントを表示
prsource=abs((Pm1.').*inv((Asource').*Asource+eps_source0*eye(length(x)).*cross_source));
this script gives me a good result but the diagonal of the matrix has maximum value ( which is not appropriate )

2 件のコメント
Suvansh Arora
2022 年 11 月 11 日
In order to understand this further, can you please let me know the following details:
Jan
2022 年 11 月 11 日
Summary: You use a formula and find the result not appropriate. How can we help you based on this lean information?
回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Operating on Diagonal Matrices についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!