How can I change the Nan values in a matrix by the values in cells array?
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f=[1 nan 3 4 5 6;nan 3 nan 5 6 7;3 nan 5 6 nan 8; 4 5 6 7 8 nan;5 6 nan 8 9 0;6 7 8 nan 0 2]
% I want to replace each nan values by one of the following data
data=[8 0 5 9 7 3 6 4]
Input_variables = num2cell(data)
Input_variables{:}
% it works till here. Then, when I want to have the replacment:
f(Input_variables{:})
% I got this error:
Index in position 1 exceeds array bounds. Index must not exceed 6.
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採用された回答
VBBV
2022 年 11 月 1 日
f(pt) = cell2mat(data)
Use cell2mat
6 件のコメント
VBBV
2022 年 11 月 1 日
編集済み: VBBV
2022 年 11 月 1 日
f(pt) = cell2mat(double(var))
Ok. That's because the above input is incorrect since the cell2mat takes cell arrays as input and converts to numeric array . But double(var) is not a cell array data type. It's already numeric,hence it's shows error when it encounters incorrect brace such as ( or [ Cell arrays begin with '{'. e.g. in this line
f={1 nan 3 4 5 6;nan 3 nan 5 6 7;3 nan 5 6 nan 8; 4 5 6 7 8 nan;5 6 nan 8 9 0;6 7 8 nan 0 2};
Hope this clears your doubt
その他の回答 (1 件)
Akira Agata
2022 年 11 月 1 日
If you want to replace NaN by the given value in linear index order, the following will be one possible solution:
% Given matrix
f = [...
1 nan 3 4 5 6;...
nan 3 nan 5 6 7;...
3 nan 5 6 nan 8;...
4 5 6 7 8 nan;...
5 6 nan 8 9 0;...
6 7 8 nan 0 2];
% Given data value
data = [8 0 5 9 7 3 6 4];
% Linear index of NaNs in the matrix f
pt = find(isnan(f));
% Replace NaN by data value
f(pt) = data;
% Show the result
disp(f)
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