フィルターのクリア

To find values by using position vector

3 ビュー (過去 30 日間)
Xia
Xia 2015 年 3 月 18 日
コメント済み: Xia 2015 年 3 月 18 日
Suppose matrix A=[1 3 5 7 9]. The position vector is known, which is, say, B=[ 3 4 ]. So the intended answer should be [ 5 7 ] which are elements at the 3rd and 4th places. Is there a function to achieve this? In fact the matrix A is high dimensional and there are many position vectors, and for loops seem not the most effective way...
Thanks in advance.

採用された回答

the cyclist
the cyclist 2015 年 3 月 18 日
answer = A(B)
  1 件のコメント
Xia
Xia 2015 年 3 月 18 日
Thank you so much. I must be too stupid to ignore the basic indexing. Thanks for your help!

サインインしてコメントする。

その他の回答 (1 件)

Guillaume
Guillaume 2015 年 3 月 18 日
It's very basic matrix indexing:
A=[1 3 5 7 9];
B=[ 3 4 ];
C = A(B)
For N-d matrices, you may have to use sub2ind to go from coordinates to linear indices.
  1 件のコメント
Xia
Xia 2015 年 3 月 18 日
Thank you Guillaume. You are right it's really basic and I learned from you. Again thanks for your time my friend!

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by