Getting just the time in Date-time cell
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Hello Please can someone help me get just the time in this date-time cell array?
I will appreciate the efforts.
attached is the data.
the first 10 rows looks like this and i want a new row with just the time such [12:33:00 12:34:00 12:35:00] and so on
'16.09.2020 12:33:00'
'16.09.2020 12:34:00'
'16.09.2020 12:35:00'
'16.09.2020 12:36:00'
'16.09.2020 12:37:00'
'16.09.2020 12:38:00'
'16.09.2020 12:39:00'
'16.09.2020 12:40:00'
'16.09.2020 12:41:00'
'16.09.2020 12:42:00'
thanks
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採用された回答
Florian Bidaud
2022 年 10 月 28 日
Hi
for i = 1:length(txt(:,1))
if ~isempty()
txtSplit = strsplit(txt{i,1},' ');
txt{i,2} = txtSplit{2};
end
The value when the time is 00:00 is empty, so you will have to add the following check :
for i = 1:length(txt(:,1))
txtSplit = strsplit(txt{i,1},' ');
if length(txtSplit) == 1
txt{i,2} = '00:00:00';
else
txt{i,2} = txtSplit{2};
end
end
その他の回答 (1 件)
Steven Lord
2022 年 10 月 28 日
I would turn the text representation of the dates and times into a datetime array then call the timeofday function on that array. If you need the representations as a string you can call string on the duration array created by timeofday.
s1 = {'16.09.2020 12:33:00'
'16.09.2020 12:34:00'
'16.09.2020 12:35:00'
'16.09.2020 12:36:00'
'16.09.2020 12:37:00'
'16.09.2020 12:38:00'
'16.09.2020 12:39:00'
'16.09.2020 12:40:00'
'16.09.2020 12:41:00'
'16.09.2020 12:42:00'};
dt = datetime(s1)
du = timeofday(dt)
s2 = string(du)
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