How to delete adjacent values

Hello

I have a vector of 1400x1 with several adjacent values (values with a difference of less than 1).

For example, my data looks like

A = [1 5 6 7 8 9 10 11 12 20 21 22 23]'

I'd like to delete the row that is adjacent to the previous one, so my expected outcome will be [1; 5; 20]

Any ideas on how to do this? I appreciate your help!

Answer 1

[Davide Masiello]

A = [1 5 6 7 8 9 10 11 12 20 21 22 23];
A([false,diff(A) == 1]) = []

A = 1×3

1 5 20

[Nao]

thank you so much for your swift response.

I get an error with this saying:

Error using horzcat

Dimensions of matrices being concatenated are not consistent

Probably because the data is lined vertically in rows (its a vector of 1400 x 1). I'm very new at this so apologize for my lack of understanding;(

[Davide Masiello]

Yes, if you have a column vector then you need to write

A([false;diff(A) == 1]) = []

[Nao]

it worked!! thank you so much!!

[Image Analyst]

But since you said "a difference of less than 1" you'd want <1 instead of == 1

A([false;diff(A) < 1]) = []

Of course then your expected outcome is not right. Maybe you mean "a difference of 1 or less" in which case it would be

A([false;diff(A) <= 1]) = []

[Nao]

thats a great point! thank you!