Finding the most common element in the first row of a matrix

Hi there

I have a matrix A, and I am wanting to take the first non zero element of each column. For example, for

A =[
    
         1     2     0     1,
         4     1     2     2,
         2     3     4     3,
         3     4     1     4
    ]

I want to have

1 2 2 3

and then find the most common element.

I looked at previous answers, and used the following code

c=arrayfun(@(x)find(A(:,x),1,'first'),1:size(A,2));

The above code works, but when I use it in a loop of size more than 10 it does not work anymore, giving me an error. I wonder if there is cleaner syntax to use here. Thanks.

[Bruno Luong]

"The above code works"

Sorry it looks like an arbitrary code to me.

Answer 1

[Bruno Luong]

Use mode command

[v,f]=mode([ 2 3 4 5 5 5 6 7 7])

v = 5

f = 3

[Josue Ortega]

Brilliant thanks

[Josue Ortega]

Ah sorry I understand now why I wanted that. I do not want the most common value, I want the most common value of each column that is not zero.

A=[ 1 2 0 3;

2 0 3 4]

I want the answer to be 2.

[Bruno Luong]

I don't like moving question. I't a waste of time for me. I'll deltete my answer no point to comment further.