creating a frame

2 ビュー (過去 30 日間)
PChoppala
PChoppala 2011 年 10 月 14 日
Hi
Want to clarify a simple doubt I have, which was posted earlier, but had not got a reply.
Does
a = randn(20,20)
imshow(a, [ ])
create a frame with 20x20 pixel, size of each pixel being 1x1, the values of the pixels are Gaussian and the intensity(values of the pixels) are gray linear scale?
Does
a = 3*randn(20,20)
imshow(a, [ ])
create a frame with the same specifications, now that the values are Gaussian with a standard deviation of '3'??
Awaiting your advice
Cheers
P

回答 (1 件)

Walter Roberson
Walter Roberson 2011 年 10 月 14 日
No, and No.
randn() cannot produce numbers beyond +/- realmax. No fixed finite range of numbers can have a gaussian distribution. A gaussian distribution has an infinite tail, always.
  1 件のコメント
PChoppala
PChoppala 2011 年 10 月 14 日
Well, can you please advise what I should use?
I was assuming randn gives uniformly distributed numbers...to be Gaussian.
Anyway, can you help me to get a frame with the above specifications?

サインインしてコメントする。

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by