Why this piece of code gives error?

1 回表示 (過去 30 日間)
Sadiq Akbar
Sadiq Akbar 2022 年 10 月 16 日
コメント済み: Sadiq Akbar 2022 年 10 月 16 日
The following piece of code gives error:
Positions=rand(30,3);
fobj=@fun4sn0;
for i=1:size(Positions,1)
Fit(i) = fobj(Positions(i,:));
end
The error it gives is as:
Array indices must be positive integers or logical values.
Error in fun4sn0 (line 18)
xo(1,k)=xo(1,k)+u(i)*exp(-1i*(k-1)*pi*cosd(u(P+i)));
Error in abc (line 4)
Fit(i) = fobj(Positions(i,:));
  1 件のコメント
KSSV
KSSV 2022 年 10 月 16 日
Show us your function @fun4sn0

サインインしてコメントする。

採用された回答

Walter Roberson
Walter Roberson 2022 年 10 月 16 日
Positions=rand(30,3);
Three columns
Fit(i) = fobj(Positions(i,:));
You pass in one row at a time, so you pass in a vector with one row and three columns.
function e=fun4sn0(pop)
where it is received as pop
C = size(pop,2);
P=C/2;
3 columns so C is 3 and P is 1.5
for i=1:P
i is 1:1.5 which will be just 1
xo(1,k)=xo(1,k)+u(i)*exp(-1i*(k-1)*pi*cos(u(P+i)));
P is 1.5 so P+i will be 2.5 and you will be indexing u at 2.5 which is not a valid index
u=[25 45 ];% desired vector
You hard-coded u to be length 2 but you can see that you are indexing u according to the size of the input vector, which will be a problem if the input gets larger.
  1 件のコメント
Sadiq Akbar
Sadiq Akbar 2022 年 10 月 16 日
Thanks a lot for your help.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeChassis Systems についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by