# plotting lat, lon, altitude, variable

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Sagar 2015 年 3 月 9 日
コメント済み: Chad Greene 2015 年 3 月 16 日
I have 3 vectors of latitude, longitude, and elevation respectively. I also have a corresponding 3d matrix of size latitude*longitude*elevation which contains some data (Temperature). I want to display the Temperature data in 3d space. What is the best way to do this? Note: I don't want to use trisurf because it requires reshaping the matrix into 3 separate vectors, with which I found difficulty in tracking the data points.
Many thanks.
-Sagar

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### 採用された回答

Chad Greene 2015 年 3 月 11 日
You can try pcolor3, although it does not work for Matlab 2014b.
% Some data:
[lon,lat,z] = meshgrid(-180:3:180,-90:2:90,0:50:1000);
T = 20 - .1*abs(lat) - .01*z + sind(lon);
% Plot dataset:
pcolor3(lon,lat,z,T);
xlabel('longitude')
ylabel('latitude')
zlabel('elevation (m)')
title('temperature or something')
axis tight

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### その他の回答 (3 件)

Sagar 2015 年 3 月 12 日

Hi Chad, thanks a lot. I tried pcolor3 that you suggested, but with no success.
Please let me know if I did something wrong. I did:
pcolor3(X, Y, Z, permuted_ext_mean); % X, Y, Z and permuted_ext_mean all have 72*85*208 size.
I got following error in Matlab 2013b. Also, it would be great if you could put a colorbar in the output image. Error using interp3/stripnanwrapper (line 204) Insufficient finite values to interpolate.
The closest one I found for my purpose is isosurface, although I am not completely satisfied: surf2 = isosurface(X, Y, Z, permuted_ext_mean, isovalue);
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Sagar 2015 年 3 月 14 日
Here is what I got with pcolor3, I am fully satisfied now. Thanks Chad.

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Chad Greene 2015 年 3 月 14 日
Great! You may also want to add a coast line for context as shown here.
##### 1 件のコメント表示非表示 なし
Sagar 2015 年 3 月 15 日
Hi Chad, that is a great suggestion and I am trying to do that as below. Is there a way to specify the range of latitude and longitude, say, in my case, 0 to 40N, -20 to 70E (so the length of the two vectors would be unequal). c = load('coast.mat'); plot(c.long,c.lat) view (3)

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Sagar 2015 年 3 月 15 日
Never mind! I was able to plot as I wanted with a small tweak. This is what I did:
long (long < -20 | long > 70 = NaN;
lat (lat < 0.00 | lat > 40.00) = NaN;
plot (lat, long);
##### 1 件のコメント表示非表示 なし
Chad Greene 2015 年 3 月 16 日
Or similarly,
long(~in) = NaN;
lat(~in) = NaN;

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