How to use if condition inside for loop without breaking the loop?

Hi everyone,
I have review many post related to use of if loop inside loop in such a way that if did not influnec the runing loop. However, i am facing probelm while implementing the same approach.
Here os waht i attempt so far:
for kk=2:3
s1=t_d(t_d(:,1)>= CE_L(kk) & t_d(:,1)<= CE_U(kk),:);
s2=v_d(v_d(:,1)>= CE_L(kk) & v_d(:,1)<= CE_U(kk),:);
if length(s1) == length(s2)
continue
S=[s1 s2];
t=S(:, 1);
t=(t-t(1)); %time (days) (initial offset removed)
ser1=S(:, 2)-mean(S(:,2)); % series 1 minus its mean
ser2=S(:, 4)-mean(S(:,4)); % series 2 minus its mean
end
end
However, my for loop stop working when if condition not satisified. Whereas, I want my for loop move to next iteration, but i didn't. May somene suggest how can i fix this.
Thank you!

5 件のコメント

KSSV
KSSV 2022 年 10 月 10 日
Why do you think for loop stopes when if condition is not met?
Torsten
Torsten 2022 年 10 月 10 日
Maybe you mean
for kk=2:3
s1=t_d(t_d(:,1)>= CE_L(kk) & t_d(:,1)<= CE_U(kk),:);
s2=v_d(v_d(:,1)>= CE_L(kk) & v_d(:,1)<= CE_U(kk),:);
if length(s1) == length(s2)
continue
end
S=[s1 s2];
t=S(:, 1);
t=(t-t(1)); %time (days) (initial offset removed)
ser1=S(:, 2)-mean(S(:,2)); % series 1 minus its mean
ser2=S(:, 4)-mean(S(:,4)); % series 2 minus its mean
end
Andi
Andi 2022 年 10 月 10 日
@Torsten earlier attepmed the way you suggets but still i did not get any output and no error as well.
Andi
Andi 2022 年 10 月 10 日
編集済み: Andi 2022 年 10 月 10 日
@KSSV becsue i know for few interation if condition satisify and for few not. Whereas, i did not get any output.
For exmaple when kk=9, the dimensions are equal but still there is no output
for kk=9:9
s1=t_d(t_d(:,1)>= CE_L(kk) & t_d(:,1)<= CE_U(kk),:);
s2=v_d(v_d(:,1)>= CE_L(kk) & v_d(:,1)<= CE_U(kk),:);
if length(s1) == length(s2)
continue
end
S=[s1 s2];
t=S(:, 1);
t=(t-t(1)); %time (days) (initial offset removed)
ser1=S(:, 2)-mean(S(:,2)); % series 1 minus its mean
ser2=S(:, 4)-mean(S(:,4)); % series 2 minus its mean
end
and when i delete if condition i get output :
for kk=9:9
s1=t_d(t_d(:,1)>= CE_L(kk) & t_d(:,1)<= CE_U(kk),:);
s2=v_d(v_d(:,1)>= CE_L(kk) & v_d(:,1)<= CE_U(kk),:);
S=[s1 s2];
t=S(:, 1);
t=(t-t(1)); %time (days) (initial offset removed)
ser1=S(:, 2)-mean(S(:,2)); % series 1 minus its mean
ser2=S(:, 4)-mean(S(:,4)); % series 2 minus its mean
end
Ghazwan
Ghazwan 2022 年 10 月 10 日
The structure of for loop of Torsten is correct. The issue you are having may be related to the data. Perhaps you need to practice the for-loop-continue structure on simpler matrices first.

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 採用された回答

Andi
Andi 2022 年 10 月 10 日

0 投票

for kk=9:9
s1=t_d(t_d(:,1)>= CE_L(kk) & t_d(:,1)<= CE_U(kk),:);
s2=v_d(v_d(:,1)>= CE_L(kk) & v_d(:,1)<= CE_U(kk),:);
if length(s1) ~= length(s2)
continue
end
S=[s1 s2];
t=S(:, 1);
t=(t-t(1)); %time (days) (initial offset removed)
ser1=S(:, 2)-mean(S(:,2)); % series 1 minus its mean
ser2=S(:, 4)-mean(S(:,4)); % series 2 minus its mean
end

その他の回答 (1 件)

Allen
Allen 2022 年 10 月 10 日

0 投票

@Adnan Barkat, it appears that your for-loop is functioning properly. However, you appear to be overwriting ser1 and ser2 during each iteration of the loop, which is returning only a single result from the last instance the loop runs.

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