How do I access and plot thetadot vs. time from function I have created?
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Shlok Pravinbhai Kansara
2022 年 10 月 8 日
編集済み: Shlok Pravinbhai Kansara
2022 年 10 月 8 日
function thetadot= oscltr(t,theta)
A= [0 0 0.5 0 0 0; 0.5 0 0 0 0 0.5; 0.5 0.5 0 0 0 0; 0 0.5 0 0 0 0; 0 0 0.5 0 0 0; 0 0 0 0.5 0.5 0]; % edge weight matrix
D= [0.5 0 0 0 0 0; 0 1 0 0 0 0; 0 0 1 0 0 0; 0 0 0 0.5 0 0; 0 0 0 0 0.5 0; 0 0 0 0 0 1]; %Diagonal in-degree matrix
L= D-A; %Laplacian matrix
N=6;
K=50;
wi=[1; 1.1 ;0.9; 0.85; 2; 2.1];
thetadot=wi-(K/N)*L*theta;
end
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採用された回答
Walter Roberson
2022 年 10 月 8 日
Please see my response at https://www.mathworks.com/matlabcentral/answers/1818985-how-to-work-variables-outside-function#answer_1068360 discussing why it is unlikely that you want to access the internal variables computed by an ode function: such a record would have far too many entries and would also not have entries for most of the time steps.
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Ghazwan
2022 年 10 月 8 日
編集済み: Walter Roberson
2022 年 10 月 8 日
There are several ways, one of whith would be
Dtheta=diff(theta) %theta = values
Dtime=diff(time) %time = time values.
ThetaDot = Dtheta./Dtime.
plot(Dtheta,time) % you have to be careful in case there is 0/0 somewhere.
2 件のコメント
Walter Roberson
2022 年 10 月 8 日
I recommend using gradient() instead. The timestep for ode45 is typically irregular.
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